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Lemur [1.5K]
3 years ago
15

Geometry Basics Test

Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0

Answer:

P=40

Step-by-step explanation:

find the distance between each vertices:

between the following points to find the length of each sides, octagon has 8 sides , since it is regular pentagon the distance between each vertices =5

the length of each side of octagon=5

to check :d=√(x2-x1)²+(y2-y1)²

(-2,-4) and (1,0) , d=√[(1-(-2)]²+(0+4)² =√3²+4², d=5

(1,0) and (1,5)  , d= 5

(1,5) and (-2,9) ,  d=5

(-2,9) and (-7,9) , d=5

(-7,9) and (-10,5) , d=5

(-10,5) and(-10,0) , d=5

(-10,0) and(-7,-4), d= 5

(-7,-4) and (-2,-4), d=5

perimeter of octagon = 8a ( a is the length of the side)

p=8(5)

P=40

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Q₃ - Q₂ > Q₂ - Q₁

$550,000 > $100,000

Therefore, the distribution is expected to be right skewed.

Since the distribution is right-skewed, the median would best represent a typical observation in the data.

Since the distribution is right-skewed, The inter-quartile range (IQR) would be a better choice to represent the variability of data.

Step-by-step explanation:

Housing prices in a country where 25% of the houses cost below $350,000.

Which means that first quartile is Q₁ = $350,000

50% of the houses cost below $450,000.

Which means that second quartile is Q₂ = $450,000

75% of the houses cost below $1,000,000

Which means that third quartile is Q₃ = $1,000,000

Recall that the distribution will be symmetric if the following relation holds true

Q₃ - Q₂ = Q₂ - Q₁

Q₃ - Q₂ = $1,000,000 - $450,000 = $550,000

Q₂ - Q₁ = $450,000 - $350,000 = $100,000

Hence the distribution is not symmetric since

Q₃ - Q₂ ≠ Q₂ - Q₁

The distribution is right skewed since

Q₃ - Q₂ > Q₂ - Q₁

$550,000 > $100,000

Therefore, the distribution is expected to be right skewed.

Since the distribution is right-skewed, the median would best represent a typical observation in the data

Therefore, A typical observation is best represented by the median.

Since the distribution is right-skewed, The inter-quartile range (IQR) would be a better choice to represent the variability of data.

Therefore, the variability in the observations is best measured by the inter-quartile range (IQR).

Note:

For a symmetric distribution, the mean would best represent a typical observation in the data and the variability of observations would be best represented using the standard deviation.

4 0
4 years ago
Read 2 more answers
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