Answer:
The slope is 0, then the line is horizontal.
y = 6
Step-by-step explanation:
Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
<span>The <u>correct answer</u> is:
B) 3log</span>₅<span>(x-4).
Explanation<span>:
To stretch a function by a factor of 3, we multiply the function by 3. This eliminates A and D.
To translate a function 4 units right, we add -4 to the variable before anything else is applied to it; this eliminates C.
In choice B, the log function is multiplied by 3, which gives us our vertical stretch; and the x is subtracted by 4 before anything else is applied to it, so it is translated 4 units right.</span></span>
The estimate the total cost to rent 3 movies and buy popcorn, a soda, and a candy bar is $18. option C
<h3>Total cost</h3>
This is the summation of all units cost of items or the results of adding all cost(fixed and variable)
Cost of movies = $3.75
= $4.00 to the nearest dollar
Cost of snacks (drinks, popcorn, candy bars) = $1.89 each
= $2.00 to the nearest dollar
Cost to rent 3 movies and buy popcorn, a soda, and a candy bar.
Total cost = (Cost of movies × number of movies) + cost of popcorn + cost of soda + cost of candy bar
= (4 × 3) + 2 + 2 + 2
= 12 + 2 + 2 + 2
= $18
Therefore, the estimate the total cost to rent 3 movies and buy popcorn, a soda, and a candy bar is $18. option C
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