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Leviafan [203]
3 years ago
6

How do I get the area of an irregular shape

Mathematics
2 answers:
Ivanshal [37]3 years ago
4 0

which one????????????????????


ladessa [460]3 years ago
4 0

just split the irregular shape to two shapes and find the area of both of them and add them together, is there any more questions please ask?

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ILL MARK YOU BRAINLEST IF YOU AWNSER PLEASE!! look at the photo and what is the measure of BMC?help me please!!
Lesechka [4]
2x + (x+9) = 90
3x + 9= 90
3x= 81
x= 27
Now plug in 27 to (x+9)
27+9= 36
Final Answer = 36
6 0
3 years ago
How is the quotient 80,000÷2000 different from the quotient 80,000÷200 or 80,000÷20
Olegator [25]
 2,000, 200 and 20 are similar except for the number of zeros.
You can remove a zero from each to equal the number of zeros in the divisor.  So 80,000 ÷ 2,000 is equivalent to 80 ÷ 2 = 40  you just remove the 3 zeros
80,000 ÷ 200 is equivalent to 800 ÷ 2 = 400 you just keep removing 0s like for instance this time it was 2 lastly 80,000 ÷ 20 only allows us to remove 1 zero 8,000 ÷ 2 = 4,000. The smaller the divisor the greater the quotient when dividing the same number like for instance in this example 80,000
3 0
3 years ago
The quadrilateral ABCD has area of 58 in2 and diagonal AC = 14.5 in. Find the length of diagonal BD if AC ⊥ BD.
azamat

Answer:

(look in the the Step by step)

Step-by-step explanation:

When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.

.. A = (1/2)*d₁*d₂

Substituting the given information, this becomes

.. 58 in² = (1/2)*(14.5 in)*d₂

.. 2*58/14.5 in = d₂ = 8 in

The length of diagonal BD is 8 in.

4 0
3 years ago
The side of cube is 3m 30cm long, find out its volume​
Anettt [7]
90 volume because 3 multiples by 30 = 90
7 0
3 years ago
If x and y are both negative when is x-y positive
Vladimir [108]
X-y is positive when y is further away from 0, compared to x. In other words, when y is a larger negative

For example
x = -2
y = -5

x-y = -2-(-5) = -2+5 = 3
7 0
4 years ago
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