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alexira [117]
3 years ago
15

I need help ASAP!!!

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
6 0

I am 99% sure it’s B

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The polygons in each pair are similar. find the missing side length.​
nydimaria [60]

Given:

The polygon in the given figure are similar.

To find:

The missing side length.​

Solution:

We know that the corresponding sides of similar figures are proportional.

The given polygons are similar, so the their corresponding sides are proportional.

\dfrac{x}{15}=\dfrac{32}{40}=\dfrac{32}{40}

So, the missing values in the equation of proportion are 15, 40, 32 respectively.

On solving the above equation, we get

\dfrac{x}{15}=\dfrac{4}{5}=\dfrac{4}{5}

\dfrac{x}{15}=\dfrac{4}{5}

x=\dfrac{4}{5}\times 15

x=12

Therefore, the value of x is 12.

4 0
3 years ago
At Hatfield Elementary School, there are 504 students in 7 classes. Each class has the same number of students. What is a good e
gizmo_the_mogwai [7]
72 is the correct number.

72 multiplied by 7 is 504
3 0
4 years ago
Rectangle ABCD is transformed to A'B'C'D' by a
salantis [7]

Answer:

c. 3

Step-by-step explanation:

You just multiply the pre image points by 3 and you get the image.

3 0
3 years ago
Read 2 more answers
Am I correct? If not please explain why!
Kipish [7]

yes, you are correct. every input corresponds to only one output

6 0
3 years ago
f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
4 years ago
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