What is 26.5 rounded to the nearest hundredth??

1 answer:

8 0

Remember your Number system
After the decimal point to the right, the next digit is the TENTH, and next is HUNDREDTH.

So for 26.5 = 26.500.
The tenth digit is 5, and the Hundredth is 0.
After the hundredth digit which is 0, the next digit is also 0.
The second 0 is not up to 5, so we would not add to the first zero.
(Was it 5, or above, we would have added 1 to first zero)

So the answer is 26.50. If the next digit after the hundredth digit was 5 or more the answer would have been 26.51.

But for this question the answer is 26.50 to the nearest hundredth. Cheers.

You might be interested in

PPPLLLLEEEAASSSEEEE HHHEEEELLLLPPPPP!!!!!!!

Yuliya22 [10]

Answer:

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Step-by-step explanation:

Because the center of dilation is at (0, 0), or the origin, we can just multiply the x and y values of each point by the scale factor of 13.

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Read more on Brainly.com - brainly.com/question/11445104#readmore

4 0

3 years ago

I have no idea how to do this

lakkis [162]

Add them all together and you’ll get your answer

sorry if this wasn’t any help or poorly explained

8 0

2 years ago

Question 13 plz show ALL STEPS so I can learn thnx

evablogger [386]

9514 1404 393

Answer:

a) (x³ -x² +x +2) +2/(x+1)

b) (x² +2x -5) +6/(x+3)

Step-by-step explanation:

Polynomial long division is virtually identical to numerical long division, except that the quotient term does not require any guessing. It is simply the ratio of the leading terms of the dividend and divisor. As with numerical long division, the product of the quotient term and the divisor is subtracted from the dividend to form the new dividend for the next step.

The process stops when the dividend is of lower degree than the divisor.

In part (a), you need to make sure the dividend expression has all of the powers of x present. This means terms 0x³ and 0x² must be added as placeholders in the given dividend. They will become important as the work progresses.