4 years ago

Jack has a rectangular sticker that is 6 centimeters long and 4 centimeters wide.

Mathematics

1 answer:

Solnce55 [7]4 years ago

8 0

Its c because 6*4 = 24
Thats how you find the area

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bruce is playing with a set of base-ten blocks. he has 65 ten-blocks and 7 one-blocks. what is the value of his blocks

Oksi-84 [34.3K]

The 65 tens blocks can be solved by doing 65x10 which is 650. the 7 ones blocks can be solved by 1x7 which is 7 so you then add up 650 and 7 to get a grand total of 657

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4 years ago

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irga5000 [103]

Answer:

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Step-by-step explanation:

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3 years ago

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Round 7,298,341 to the nearest 10,000

WITCHER [35]

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3 years ago

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Ira Lisetskai [31]

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3 years ago

If f(x)=x squared-2x and g(x) = 6x+4 for which is a value of x does (f+g)(x) =0

ra1l [238]

Answer:

For $x = -2$

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

In this question:

$f(x) = x^2 - 2x$

$g(x) = 6x + 4$

$f(x) + g(x) = (f+g)(x) = x^2 - 2x + 6x + 4 = x^2 + 4x + 4$

Which is a value of x does (f+g)(x) =0

$x^2 + 4x + 4$

Quadratic equation with $a = 1, b = 4, c = 4$

$\Delta = 4^{2} - 4*1*4 = 0$

$x_{1} = \frac{-4 + \sqrt{0}}{2} = -2$

$x_{2} = \frac{-4 - \sqrt{0}}{2} = -2$

For $x = -2$

7 0

3 years ago