Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
24/5 = (20 + 4)/5 = 20/5 + 4/5 = 4 + 4/5
= 4 4/5
Answer:
193 packets
Step-by-step explanation:
Each morning they order with a shipping fee of $10 daily.
Considering they order all 7 days of the week, so the total shipping fee for the week would be:
7 * $10 = $70
Their budget for the week is $554, out of which $70 is for shipping for the week, so remaining balance would be:
554 - 70 = $484
This 484 dollars are for coffee packets that cost $2.50 each, so the number of packets would be:
484/2.50 = 193.6
You can't order fractional packets so 193 packets is the max in this budget
Answer: the answer is x+8= 1
BG = 40. Equation: 4(3) + 8 + 20 = 40.
