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3 years ago

What is the slope of y=3x and what's the Y-intercept of y=3x

Mathematics

1 answer:

kompoz [17]3 years ago

4 0

The slope is 3 or 3/1 and the Y intercept is 0 or (0,0) because in y=mx+b, is it the slope (3) and b is the y intercept (0)

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What are the zeros of the function f(x)=x^2-3x?

Serjik [45]

X= 0,3

Do you want me to explain why?

5 0

3 years ago

HELP PLEASE

RUDIKE [14]

We have the following equation:
y = -2x2 + 2x + 2
We look for the vertex of the parabola. For this, we derive the given equation:
y '= - 4x + 2
We match zero:
0 = -4x + 2
We clear x:
4x = 2
x = 2/4
x = 1/2
We evaluate the function for x = 1/2:
y = -2 * (1/2) ^ 2 + 2 * (1/2) + 2
y = 2.5
The vertice of the parabola is:
(x, y) = (1/2, 2.5)
We now look for the value of the function for x = 6:
y = -2 * (6) ^ 2 + 2 * (6) + 2
y = -58
Answer:
The vertice of the parabola is:
(x, y) = (1/2, 2.5)
the value of the function for x = 6 is:
y = -58

7 0

2 years ago

What is the value of 8x+2x when x=6?

Ivan

Answer:
60
solution:
8(6)+2(6)
48+12=60

4 0

2 years ago

What is the initial value of the exponential function shown on the graph? <br> 0<br> 1<br> 2<br> 4

wariber [46]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

You have a bag of chocolate candy. Ten of them are red, 7 are brown, 12 are green, and 9 are blue. What is the probability that

Alona [7]

Answer: The correct option is (A) $\dfrac{10}{37}.$

Step-by-step explanation: Given that in a bag of chocolate candy, ten of them are red, 7 are brown, 12 are green, and 9 are blue.

We are to find the probability that we pick a red candy, given that we have already picked a blue candy and have not replaced it.

We have

Probability of picking a blue candy is given by

$P_b=\dfrac{\textup{number of blue candies}}{\textup{total number of candies}}\\\\\\\Rightarrow P_b=\dfrac{9}{10+7+12+9}\\\\\\\Rightarrow P=\dfrac{9}{38}.$

Now, since we have already picked a blue candy and did not replace it, so total number of candies left in the bag = 10+7+12+8 = 37.

There are 10 red candies in the bag,

so the probability of picking a red candy given that we have already picked a blue candy and have not replaced it will be

$P_{r/b}=\dfrac{\textup{number of red candies in the bag}}{\textup{total number of candies left in the bag after picking a blue candy}}\\\\\\\Rightarrow P_{r/b}=\dfrac{10}{37}.$

Thus, the required probability is $\dfrac{10}{37}.$

Option (A) is correct.

7 0

3 years ago

Read 2 more answers