The graph would be continuous because height is a continuous variable as if can be exactly, say, 167 cm, but it can also be 153.53 cm.
There are three possible results when a plan intersects with a three-dimensional figure and these are:
a point
a line
a plane
The first step in describing the result is to determine first how the plane and the figure intersects.
There would be a hole when x = -4.
If you factor both the top and the bottom, you will see that the factor (x + 4) is in both the numerator and denominator. Therefore, the would be a hole when x = -4 because that would also make the denominator 0.
Answer:
Step-by-step explanation:
a: Wrong. The first thing that you have to notice is that the sum goes to infinity. If you want k=4 to be the last condition, then take out the 3 dots.
b: That's the answer.
c: wrong. You get a real mess when you let set k = 0. Try it on your calculator.
1 ÷ 0 = Watch carefully as your calculator mentally melts down.
d: wrong. It's just not right. The highest power is k^2. There is no way to get k^3
well, the triangle is an isosceles, so it twin sides, and the twin sides make twin angles, as we see by the tickmarks on A and C, meaning AB = BC.
![\bf x+4=3x-8\implies 4=2x-8\implies 12=2x\implies \cfrac{12}{2}=x\implies 6=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ AC\implies x+4\implies 6+4\implies 10](https://tex.z-dn.net/?f=%5Cbf%20x%2B4%3D3x-8%5Cimplies%204%3D2x-8%5Cimplies%2012%3D2x%5Cimplies%20%5Ccfrac%7B12%7D%7B2%7D%3Dx%5Cimplies%206%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20AC%5Cimplies%20x%2B4%5Cimplies%206%2B4%5Cimplies%2010)
