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Gwar [14]
3 years ago
15

Which equations are equivalent to 1/5 + 2/3 |2-xl = 4/15? Check all that apply.

Mathematics
2 answers:
Kazeer [188]3 years ago
4 0

Answer:

(2 - x ) = 1 / 10

Step-by-step explanation:

1 / 5 + 2 / 3 (2 - x ) = 4 / 15

Subtract 1 / 5 from both sides

2 / 3 (2 - x ) = 4 / 15 - 1 / 5

2 / 3 (2 - x ) = 1 / 15

Multiply 3 / 2 on both sides

(2 - x ) = 1 / 15 * 3 / 2

(2 - x ) = 1 / 10

vivado [14]3 years ago
3 0

Answer:

its the 1st and 3rd

Step-by-step explanation:

i answered it

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A horse ran 800 m in 40 seconds 1200 m in 60 seconds in 480 m and 24 seconds is this a proportional relationship if so what is t
Naddik [55]

Answer:

Yes this is a proportional relationship.

Equation is;

D=20T

Step-by-step explanation:

A horse run;

800m in 40 seconds

1200m in 60 seconds

and

480m inn 24 seconds

800m ÷ 40s = 1200m ÷ 60s = 480m ÷ 24s = 20

The equation here is Distance(D) = 20 × Time(T)

D=20T

It implies that the distance of the horse is directly proportional to the time it takes to run.

8 0
3 years ago
Use mathematical induction to prove that if L is a linear transformation from V to W, then L (α1v1 + α2v2 +· · ·+αnvn)= α1L (v1)
e-lub [12.9K]

Answer:

The proof is shown in the explanation below.

Step-by-step explanation:

Analysis:

The proof by induction focuses on n. In this case, let n = 1, and L^{1} will be a linear operator since L^{1} = L

The exercise will show that L^{n} is a linear operator on V and that L^{n+1} is also a linear operator on V. This, follows that:

L^{n+1} (av) = L(L^{m}(v_{1}+v_{2})\\                   = L(L^{m} (v_{1} + L^{m}v_{2})\\                   = L(L^{m}v_{1} + L(L^{m}v_{2})\\                   = L^{m+1}(v_{1}) + L^{m+1}(v_{2})

6 0
2 years ago
Read 2 more answers
What’s the slope of the line in the graph?
zloy xaker [14]

Check the picture below, let's use those two points on the line to get its slope.

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{0}}}\implies \cfrac{2}{2}\implies 1

5 0
3 years ago
Help quick please!!
Korolek [52]

Answer:

Difference of squares:

y^4−25

16x^2−81

Not difference of squares:

20m^2n^2−121

p^8−q^5

Step-by-step explanation:

y^4−25

(y²)² - 5²

16x^2−81

(4x)² - 9²

20m^2n^2−121

20 is not a perfect square

p^8−q^5

q⁵ is not a perfect square

3 0
2 years ago
Px + qy = r<br> 2px - qy = 2r<br> When solving this system of equations, x =
VladimirAG [237]
Px + qy = r
2px - qy = 2r
----------------add
3px = 3r

x = 3r/3p
x = r/p
8 0
3 years ago
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