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Artyom0805 [142]
3 years ago
6

The area of a rectangle is 63ft ^2 and the length of the rectangle is 5ft more than double the width. Find the dimensions of the

rectangle.
Mathematics
1 answer:
Tasya [4]3 years ago
4 0
---------------------------------------------------------------------------------
Define Length and Width
---------------------------------------------------------------------------------
Let the width be x
Width = x
Length = 2x + 5

---------------------------------------------------------------------------------
Form equation and solve for x
---------------------------------------------------------------------------------
x(2x + 5) = 63
2x² + 5x = 63
2x² + 5x - 63 = 0
<span>(x+7)(2x-9) = 0
</span>x = -7 (rejected, length cannot be negative) or 2x - 9 = 0
2x - 9 = 0
2x = 9
x = 9 ÷ 2 
x = 4.5 ft

---------------------------------------------------------------------------------
Find Length and Width
---------------------------------------------------------------------------------
Width = x = 4.5 ft
Length = 2x + 5 = 2(4.5) + 5 = 14 ft

---------------------------------------------------------------------------------
Answer: Width = 4.5 ft , Length = 14 ft
---------------------------------------------------------------------------------


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