Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
216/1000
Simplify it by 2
Give me a thanks if it helps!!!
Answer:
For the first one the answer is 60 idk about the 2 one tho
Step-by-step explanation:
Answer:
There is not a way that I can show you how to graph it, so I will try and explain it.
Step-by-step explanation:
(1,1)
^ ^ y-axis
x-axis
You are just going right however many, and then up however many it says.
So if it's (1,1) you will go right one space, and then up one space.
Once you have all of your points on the graph, you put a line through them.
Hope this helps! :)