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N76 [4]
3 years ago
7

A batter hits a baseball into the air

Mathematics
2 answers:
Talja [164]3 years ago
5 0

For this case we observe that we have a function of the form:

h (t)

Where,

t: independent variable

h: dependent variable

What we must do is observe the value of the dependent variable when we have a value of the independent variable.

The independent variable is:

t = 5

We note that the dependent variable for that value is:

h (5) = 75

Answer:

option 1

h (5) = 75

azamat3 years ago
4 0

The answer is h(5) = 75.

Where x=5, y=75

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Which statement correctly describes the relationship between the lengths of the sides of the triangle shown below?
Vanyuwa [196]

Answer:

B

Step-by-step explanation:

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7 0
3 years ago
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Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
3 years ago
PLEASE HELP VERY URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
diamong [38]

Q1.  Look at the picture.

C.\\y=-\dfrac{1}{3}x+3\\\\y=2x-4

Q2. Look at the picture.

A.\ 4-t

Q3.

Put the value of x = 2 to the equation 3x + y = 5:

3(2)+y=5

6+y=5       <em>subtract 6 from both sides</em>

y=-1\\\\F.\ -1

Q4.

\left\{\begin{array}{ccc}n=3m-11&(*)\\2m+3n=0&(**)\end{array}\right

Substitute (*) to (**):

2m+3(3m-11)=0            <em>use distributive property</em>

2m+(3)(3m)+(3)(-11)=0

2m+9m-33=0       <em>add 33 to both sides</em>

11m=33      <em>divide both sides by 11</em>

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Put the value of m to (*):

n=3(3)-11\\\\n=9-11\\\\n=-2

C. (3,\ -2)

Q5.

w - width

3w - length

24 in - the sum of length and width

The equation:

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w=6\ in

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A cube-shaped box has a volume of 125 cubic inches. If the box is packed full of cubes with edge lengths of 1 inch, how many cub
harina [27]

I am not sure if I am right, but this is the best I can answer.


Useing reason, and logic, my guess would be if you take 125, and divided it by 4, you would get 31.25. that should be the answer... if i am wrong, i am truely sorry. I havent been in the subject in a while...


                                                           Hope this helps.


6 0
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