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3 years ago

What is the slope of the line that passes through the points (-1 , 0) and (3 , 8).?

Mathematics

1 answer:

Zina [86]3 years ago

5 0

Let's apply the formula giving the slope:

m=(y2-y1) /(x2-x1) , let's plug:

m= (8-0) / (3-(-1)) ====> m= 2

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3. The formula to find the surface area of a sphere is to take the radius of the sphere and square it and multiply that amount b

KatRina [158]

The way to get the equation for the radius (r) is to get r by itself. So divide each side by 4pi
500/4pi=r^2
Now take the square root of each side to get the equation of r.
sqrt(500/4pi)=r

6 0

3 years ago

Read 2 more answers

Evaluate each expression please help(the crossed out ones are irrelevant)

olga nikolaevna [1]

9. 31 + 5 = 36
10. 16 - 4 = 12
12. 9
13. 44 + 34 = 78
14. 101 - 1 = 100

15. -539 ???
16. 15 ??
17. |-435| = 435

7 0

2 years ago

Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

3 years ago

What is the value of x, when -9(x-5)=x+22 1/2

Kipish [7]

Answer:

x = 2.25

Step-by-step explanation:

-9(x - 5) = x + 22 1/2

Distribute the nine and then add 9x to both sides

-9x + 45 = x +22 1/2

+ 9x + 9x

Then try to get x alone

45 = 10x + 22 1/2

-22 1/2 -22 1/2

22.5 = 10x

$\frac{22.5}{10} = \frac{10x}{10}$

2.25 = x

4 0

3 years ago

Read 2 more answers

A student is saving money to buy a microscope. The student currently has $50 and plans to save $15 every month. Write a function

Evgen [1.6K]

Answer:

Step-by-step explanation:

The student currently has $50 and plans to save $15 every month.

Let x represent the number of months that the student will save enough money to buy the microscope.

Let y represent the amount that the student saves after x months.

The function that represents the amount y (in dollars) of money that the student saves after x months will be

y = 50 + 15x

The 50 remains constant because she has already saved it

5 0

3 years ago