What are the Characteristics of theta waves
1 answer:
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Answer:
a) 138 units
b) 17 units
c) 17 units
d) Total Cost = $353.35
Explanation:
Given:
Average pizzas delivered = 200
Charge of inventory holding = 30% of cost
Lead time = 7 days
Now,
a) Economic Order Quantity =
also,
Annual Demand = 200 × 12 = 2400
Cost per Order = Cost of Box + Processing Costs
= 30 cents + $10
= $10.30
and, Carrying Cost =
=
=
= $2.575
Therefore,
Economic Order Quantity =
= 138.56 ≈ 138 units
b) Reorder Point
= (average daily unit sales × the lead time in days) + safety stock
= (
= 46.67 ≈ 47 units
c) Number of orders per year =
=
= 17.39 ≈ 17 units
d) Total Annual Cost (Total Inventory Cost)
= Ordering Cost + Holding Cost
Now,
The ordering Cost = Cost per Order × Total Number of orders per year
= $10.30 × 17
= $175.1
and,
Holding Cost = Average Inventory Held × Carrying Cost per unit
Average Inventory Held = = 69
Carrying Cost per unit = $2.575
Holding Cost = 69 × $2.575 =
$177.675
Therefore,
Total Cost = Ordering Cost + carrying cost
= $175.1 + $177.675 = $353.35
a) 22.5 m/s
The initial vertical velocity is given by:
where
u = 35 m/s is the initial speed
is the angle of projection of the ball
Substituting into the equation, we find
b) 26.8 m/s
The initial horizontal velocity is given by:
where
u = 35 m/s is the initial speed
is the angle of projection of the ball
Substituting into the equation, we find
c) 2.30 s
The time it takes for the ball to reach the maximum heigth can be found by considering the vertical motion only. This is a uniformly accelerated motion (free-fall), so we can use the suvat equation
where
is the vertical velocity at time t
is the acceleration of gravity (negative because it is downward)
At the maximum height, the vertical velocity becomes zero, ; substituting, we find the time t at which this happens:
d) 25.8 m
The maximum height can also be found by considering the vertical motion only. We can use the following suvat equation:
where
s is the vertical displacement at time t
Substituting t = 2.30 s, we find the displacement at maximum height, so the maximum height:
e) 123.3 m
In order to find how far does the ball lands, we have to consider the horizontal motion.
First of all, the time it takes for the ball to go back to the ground is twice the time needed for reaching the maximum height:
Then, we consider the horizontal motion. There is no acceleration along this direction, so the horizontal velocity is constant:
Therefore, the horizontal distance travelled during the whole motion is
So, the ball lands 123.3 m far from the initial point.