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3 years ago

O

Physics

1 answer:

Sergio [31]3 years ago

4 0

see

below

Explanation:

refractive index = speed of light in vacuum / speed of light in medium

light travels at a speed of 3.0 x 10^8 m/s in vacuum

refractive index = 3.0 x 10^8 / 2.0 x 10^8

refractive index = 1.5

hope this helps, please mark it

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Peter left town A at 13:30 and travelled towards town B at an average speed of 40mph. At 13:45 Philip left town A for town B at

skad [1K]

Answer:

fbddb

Explanation:

dsbse

8 0

3 years ago

You throw a ball straight up with an initial velocity of 15.0 m/s. It passes a tree branch on the way up at a height of 7.00 m.

Gwar [14]

Answer:

0.95 seconds

Explanation:

t = Time taken

u = Initial velocity = 15 m/s

v = Final velocity

s = Displacement

a = Acceleration = 9.81 m/s² (downward positive, upward negative)

Time taken by the ball to reach the maximum height

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-15}{-9.81}\\\Rightarrow t=1.52\ s$

Maximum height

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-15^2}{2\times -9.81}\\\Rightarrow s=11.47\ m$

Distance between maximum height of the ball and the branch is 11.47-7 = 4.46 m

So, the distance that will be covered on the way down is 4.46 m

Now

u = 0

s = 4.46

$s=ut+\frac{1}{2}at^2\\\Rightarrow 4.46=0\times t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{4.46\times 2}{9.81}}\\\Rightarrow t=0.95\ s$

Time taken by the ball from the maximum height to the tree branch is 0.95 seconds.

Total time taken from the moment the ball is thrown to reach the tree branch is 1.52+0.95 = 2.47 seconds

7 0

3 years ago

The mechanical advantage of a simple machine is 3 and its velocity ratio is 4 find its efficiency

LiRa [457]

Answer:

75%

Explanation:

Efficiency=MA/VR*100

=3/4*100

=0.75*100

=75%

6 0

2 years ago

In a previous problem, you calculated how much energy was needed to accelerate a 2,100-kg Tesla Model S from 0 to 100 km/hr, and

Naddika [18.5K]

Answer:

t=2.348s

Explanation:

First we need to calculate the Potential Energy of a Tesla to reach the 100km/h

So we know that,

$W=KE_f - KE_i = \frac{1}{2}m(V_f^2-V_i^2)=\frac{1}{2}(2100)(27.78^2)$ $W=8.1*10^5J$

Here we can to calculate the time through,

$t=\frac{W}{P}$

$t=\frac{8.1*10^5}{345*10^3}$

$t=2.348s$

5 0

3 years ago

HELP PLEASE!

ryzh [129]

Answer:

I think the second one! So sorry if it's wrong!

Explanation:

Because if it's sitting motionless, then nothing is happening to it.

7 0

3 years ago