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3 years ago

12

When driving uphill, the force of gravity is working against you and you may need to accelerate or change to _______ gear to mai

ntain your speed.?

1 answer:

Charra [1.4K]3 years ago

5 0

'Change to low gear' is your answer.

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Which of the following is a displacement?

Contact [7]

D) 3 Blocks East.

Because it is a distance specified by direction which is East.

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3 years ago

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Atmospheric pressure decreases with increment in height.<br> give reason

jekas [21]

Answer:

pressure=height × density×acc due to gravity

so

pressire is directly proportional to height hence it decreses with decrease in height

here air column height is measured upside down so decreases witn increment

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3 years ago

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what is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?

timurjin [86]

The initial velocity of go-kart is 2.5 m/s.

<u>Explanation:</u>

Here, the uniform acceleration of go-kart is given as 0.5 m/s². Also the time required by it to stop is also given as 5 s. As acceleration is the measure of change in velocity per unit time.

In this case, the velocity should be changed from a value to zero to come to rest. So the initial velocity will be positive value and final velocity is zero.

As we know the values of acceleration, final velocity and time, the initial velocity can be easily determined as follows.

$Acceleration = \frac{Final velocity -Initial velocity}{Time}$

Since, final velocity is zero, acceleration is 0.5 m/s² and time is 5 s, then,

$-0.5=\frac{-\text {Initial velocity}}{5}$

Initial velocity = 0.5 × 5 = 2.5 m/s.

So the initial velocity of go-kart is 2.5 m/s.

8 0

3 years ago

What task requires the most work, lifting a 12-kg sack 2 meters or lifting a 25-kg sack 1 meter?

MrMuchimi

Multiply the masses by the respective distances:

(12 kg) (2 m) = 24 J

(25 kg) (1 m) = 25 J

so the heavier bag takes more work to lift, and (b) is the answer.

(d) is technically correct if the sacks are carrying different contents whose masses are not equal, but since we don't know what's inside each sack, assume 12 kg and 25 kg are the masses of each sack *and* their contents.

5 0

3 years ago

The length of the minute hand of the clock is 14cm. Calculate the speed with which the tip of the minute hand moves

Molodets [167]

Speed of the tip of the minute hand=V=0.0244 cm/s

Explanation:

The angular velocity of the minute hand is given by

$\omega= \frac{2\pi}{T}$

T= time period of the minute hand=60 min=3600 s

so ω= 2 π/3600 rad/s

Now linear velocity v= r ω

r= radius of minute hand=14 cm

so v= 14 (2 π/3600)

V=0.0244 cm/s

8 0

3 years ago