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3 years ago

What is the frequency of a raido wave with a wavelength of 1.0 mm?

Physics

1 answer:

UkoKoshka [18]3 years ago

3 0

Answer:

3×10^6

Explanation:

frequency is the speed of light ( c) which is a constant number divided the wavelength

f = 3×10^6 / 1.0

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Setting goals that match your lifestyle helps improve chances that they will be reached.

Tasya [4]

Answer:

TRUE!!!!!!

Explanation:

7 0

3 years ago

Read 2 more answers

Lily took 6 hours to complete a journey at an average speed of 58 km/h. For the first 4 hours, she travelled at an average speed

arlik [135]

Answer:

92km

Explanation:

Given parameters:

Duration of the journey = 6hrs

Average speed = 58km/hr

Now, let us find the total distance of the journey;

Distance = Speed x time

Distance = 58 x 6 = 348km

So;

Average speed for the first 4hrs = 64km/hr

Time = 4hrs

Distance = 64 x 4 = 256km

For the rest of the journey, the student will cover;

= 348km - 256km

= 92km

8 0

3 years ago

A water pump draws about 9 A when connected to 240 V. What is the cost (with electrical energy at 13 cents per kWh) of running t

Fiesta28 [93]

Answer:

4.49 dollars

Explanation:

i = 9 A, V = 240 V, t = 16 h

Energy = V x i x t = 240 x 9 x 16 = 34560 W h = 34.56 kWh

The cost of 1 kWh is 13 cents.

Cost of 34.56 kWh = 13 x 34.56 = 449.28 cents = 449.28 / 100 = 4.49 dollars

8 0

4 years ago

The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5

nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

$G\frac{mM}{R^2}=m\frac{v^2}{R}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$m=11,100 kg$ is the mass of the telescope

$M=5.97\cdot 10^{24} kg$ is the mass of the Earth

$R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m$ is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

$v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s$

6 0

3 years ago

The Cajun Cliffhanger at Great AMerica is a ride in which occupants line the perimeter of a cylinder and spin in a circle at a h

12345 [234]

Explanation:

Centripetal Force is the force that keeps the object's rotation in a circular path and it's always directed towards the center of rotation. Mathematically, it is given as,

$F_{c} = \frac{mv^{2} }{r}$

From this equation it can be concluded that the centripetal force is proportional to the product of mass and the square of velocity. It is inversely proportional to the object's distance from the center.

Now in the above mentioned case, when the cylinder begins spinning very rapidly and it's speed becomes double. Then by applying the above equation we conclude that " the force will be increased four times if the speed is doubled as it is proportional to square of speed."

5 0

3 years ago