All categories

2 years ago

If two angles are supplementary, then they are not congruent. Which diagram provides a counterexample for the statement?

Mathematics

2 answers:

bekas [8.4K]2 years ago

3 0

Answer:

Step-by-step explanation:

A suplementary angle equals 180 degrees if there not congrent then there not the same amount so d would work.

Sorry if it turns out wrong!

zhenek [66]2 years ago

3 0

Answer:

Step-by-step explanation:

supplmentay angles are either of two angles whose sum is 180°

option b is two right angles (90 degree on both) add them together you get 180.

option c is 60 degrees and 120 degrees add them together to get 180 degrees.

option d is 155 degrees and add 25 degrees you get 180.

so the answer is a, because 30 degrees and add the other 30 degrees together you only get 60

You might be interested in

What is the measure of XYZ?

ASHA 777 [7]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

When a bush was first planted in a garden it was 12 inches tall after two weeks it was 120% as tall when it was first planted ho

Juliette [100K]

14.4, 120% of 12 is 100+20, 12+2.4 is 14.4

4 0

2 years ago

Graph the point (-2,-3) on the coordinate plane

atroni [7]

Answer:

The point will come in III quadrant

Step-by-step explanation:

The graph is as follows:

3 0

2 years ago

Read 2 more answers

PLEASE HURRY I HAVE 3 mins left Which relationship could be the one shown on the graph?

ss7ja [257]

Option A

Must click thanks and mark brainliest

Sorry if i am wrong

4 0

2 years ago

Find the derivative of f(x) = 2x^2 - 4x +3

ivolga24 [154]

Explanation

$2x^2-4x+3$

When taking derivatives of polynomials, we primarily make use of the power rule.

Power rule.

$\begin{gathered} f(x)=x^n \\ \text{then} \\ f^{\prime}(x)=nx^{n-1} \end{gathered}$

also, the derivate of a sum is the sum of the derivates

hence

$\begin{gathered} g(x)=f(x)+h(x)+\ldots z(x) \\ g^{\prime}(x)=f^{\prime}(x)+h^{\prime}(x)+\ldots.z^{\prime}(x) \end{gathered}$

Step 1

apply:

$\begin{gathered} f(x)=2x^2-4x+3 \\ f^{\prime}(x)=2\cdot2x^{2-1}-4(1)x^{1-1}+ \\ f^{\prime}(x)=4x^{}-4(1)x^0+3^0 \\ f^{\prime}(x)=4x^{}-4(1)(1) \\ f^{\prime}(x)=4z-4 \end{gathered}$

therefore, the answer is

8 0

11 months ago