No entiendo....................
<em>429 cm²</em>
- Step-by-step explanation:
<em>A(blue) =</em>
<em>= 2×6cm×10cm + 2×6cm×8cm + 8cm×10cm + (8cm×10cm - 5cm×4cm)</em>
<em>= 120cm² + 96cm² + 80cm² + 60cm²</em>
<em>= 356 cm²</em>
<em>A(green) =</em>
<em>= 4cm×5cm + 2×5cm×5cm/2 + 4cm×7cm</em>
<em>= 20cm² + 25cm² + 28cm²</em>
<em>= 73 cm²</em>
<em>A(total) =</em>
<em>= A(blue) + A(green)</em>
<em>= 356 cm² + 73 cm²</em>
<em>= 429 cm²</em>
The value f x when y= 5 is 2
<h3>Variations </h3>
Let the given equation be y = k/x
where k is the constant
if y = 2 when x= 5, then;
k = xy
k= 2(5)
k = 10
In order to determine the value of x when y = 5
x = k/y
x = 10/5
x = 2
Hence the value f x when y= 5 is 2
Learn more on variation here: brainly.com/question/6499629
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Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the mean salaries of college graduates
Number of sample, n = 40
Mean, u = $62, 200
Standard deviation, s = $11,766
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
62200 +/- 1.645 × 11766/√40
= 62200 +/- 1.645 × 1860.4
= 62200 +/- 3060.358
The lower end of the confidence interval is 62200 - 3060.358 =59139.642
The upper end of the confidence interval is 62200 + 3060.358 =65260.358
Therefore, with 90% confidence interval, the mean mean salaries of college graduates is between $59139.642 and $65260.358
Answer: the answer is 56
Hope this Help
Step-by-step explanation:
100%= 25
X%= 14
100%=25(1)
X% = 14(2)
100%/x% = 25/14
X%/ 100% = 14/25
X=56%
