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ExtremeBDS [4]
3 years ago
11

CAN SOMEONE PLEASE HELP ME WITH NUMBER 2

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

Step-by-step explanation:

It's B.

So the equation is x > -25. In word form, "The solution to this equation is greater than -25."

B begins at -25, and has a thick arrow pointing in the positive direction.

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Two equations are given below:
Evgesh-ka [11]

The solution to the set of equations is (0,2).

Reasoning:

m + 4n = 8 -> 0 + 4(2) = 8

m = n - 2 -> 0 = 2 - 2

6 0
3 years ago
The function f(x)=2/3x-4 was replaced with f(x+k)=2/3x-6 what is the value of k
HACTEHA [7]

Answer:

The given function f(x)=\frac{2x}{3}-4 was replaced with f(x+k)=\frac{2x}{3}-6 then the value of k is -3

that is k=-3.

Step-by-step explanation:

The given function is f(x)=\frac{2x}{3}-4\hfill (1)

and when x=x+k then f(x+k)=\frac{2x}{3}-6\hfill (2)

Now to find the value of k:

Put x=x+k in the function f(x)

f(x)=\frac{2x}{3}-4

f(x+k)=\frac{2(x+k)}{3}-4

f(x+k)=\frac{2x+2k}{3}-4\hfill (3)

Now comparing equations (2) and (3) we get

f(x+k)=\frac{2x+2k}{3}-4=\frac{2x}{3}-6

\frac{2x+2k}{3}-4=\frac{2x}{3}-6

\frac{2x+2k}{3}-4-\frac{2x}{3}+6=0

\frac{2x}{3}+\frac{2k}{3}-4-\frac{2x}{3}+6=0

\frac{2k}{3}+2=0

\frac{2k}{3}=-2

k=\frac{-2\times 3}{2}

k=-3

Therefore k=-3

Therefore the given function f(x)=\frac{2x}{3}-4 was replaced with  f(x+k)=\frac{2x}{3}-6 then the value of k is -3

that is k=-3.

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