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SIZIF [17.4K]
4 years ago
15

A positive integer is 11 more than 18 times another. Their product is 6030. Find the two integers.

Mathematics
2 answers:
andre [41]4 years ago
6 0

Answer:

 y = 335

so its 18 and 335

allsm [11]4 years ago
4 0

Answer:

18 and 335

Step-by-step explanation:

y = 18x + 11

x * y = 6030

x * (18x + 11) = 6030

18x^2 + 11x = 6030

18x^2 + 11x - 6030 = 0

(18x + 335)(x - 18) = 0

18x + 335 = 0                 x - 18 = 0

18x = -335                      x = 18

x = -335/18

x is gonna have to be a positive number...so x = 18

y = 18x + 11

y = 18(18) + 11

y = 324 + 11

y = 335

so ur numbers are 18 and 335

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3 years ago
Find two consecutive integers such that the sum of their squares is 145.
DiKsa [7]

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Step-by-step explanation:

Let x be the first of the two integers. Then, since the numbers are consecutive, x+1 is the other integer. We then know that the sum of the squares of x and x+1 is equal to 145. So, now we have the equation

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4 years ago
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Note: "sqrt" is shorthand for "square root"

==============================================

Question 2

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28/2 = 14

Therefore, sqrt(x^28) = x^14

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