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kati45 [8]
3 years ago
9

What is the equation of the line

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

c- y=4/3x

Step-by-step explanation:

hope this helps u

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If pr is 3x+14 and qr 7x-10 what is x
mr Goodwill [35]
Start the equation by putting the equations equal to each other 3x+14=7x-10
Next +10 on both sides
3x+14=7x-10
+10 +10
You are left with 3x+24=7x
because the 10's canceled each other out.
Next -3x on both sides
3x+24=7x
-3x +3x

You are left with 24= 10x
because like before the 3's canceled each other out
Now you will divide both sides by 10

24=10x
---- -----
10 10

2.4= X is the answer!
8 0
3 years ago
What is the height of this triangle?
nikklg [1K]
A = 1/2 b h
5 = 1/2 (5) h
10 = 5h
h = 10/5
h = 2

answer
2
7 0
3 years ago
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Find the quotient. 12a^3p^4 ÷ -2a^2p
777dan777 [17]

Answer:

-(6ap³)

Step-by-step explanation:

We have to find the quotients of

\frac{12a^{3}p^{4}}{-2a^{2}p}

We take the common 2a² p from the numerator

= \frac{(6ap^{3}(2a^{2}p))}{(-2a^{2}p)}

= -(6ap³)

Therefore, the quotient after division will be -(6ap³)

4 0
3 years ago
GEOMETRY!!!! K' (6,5) is the image of K after a reflection in the line y=2. what are the coordinates of K
frutty [35]

Given:

The coordinates of point K' are (6,5).

K' is the image of K after a reflection in the line y=2.

To find:

The coordinates of point K.

Solution:

Let the coordinates of point K are (a,b).

If a figure is reflected over the line y=2, then

(x,y)\to (x,2(2)-y)

(x,y)\to (x,4-y)

Using this formula, the coordinates of image of K are

K(a,b)\to K'(a,4-b)

The coordinates of point K' are (6,5).

K'(a,4-b)=K'(6,5)

On comparing both sides, we get

a=6\text{ and }4-b=5

a=6\text{ and }-b=5-4

a=6\text{ and }-b=1

a=6\text{ and }b=-1

Therefore, the coordinates of point K are (6,-1).

3 0
3 years ago
The ratio of 1 to 3 is
andreev551 [17]
1:3 that's so easy like bruh
3 0
3 years ago
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