Answer:

Step-by-step explanation:
given,
y=5√sinx
Volume of the solid by revolving

a and b are the limits of the integrals
now,



![V =25\pi [-cos x]_{\pi/4}^{\pi/2}](https://tex.z-dn.net/?f=V%20%3D25%5Cpi%20%5B-cos%20x%5D_%7B%5Cpi%2F4%7D%5E%7B%5Cpi%2F2%7D)
![V =25\pi [-cos (\pi/2)+cos(\pi/4)]](https://tex.z-dn.net/?f=V%20%3D25%5Cpi%20%5B-cos%20%28%5Cpi%2F2%29%2Bcos%28%5Cpi%2F4%29%5D)
![V =25\pi [0+\dfrac{1}{\sqrt{2}}]](https://tex.z-dn.net/?f=V%20%3D25%5Cpi%20%5B0%2B%5Cdfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%5D)

volume of the solid generated is equal to 
Similarities: They both are polynomials of degree 2, both of their graphs is a parabola, both have either 2 or 0 real solutions, they are both continuous functions over R
(DOS= difference of two squares, PST=perfect square trinomial
Differences: PST has three terms, whereas the difference of squares has 2. PST's factors are both the same, whereas DOS's elements are conjugates of each other. DOS can always be factored into two distinct polynomials with rational coefficients, whereas PST has two same polynomial factors.
$367.80 because you have to add up the purchase the owe and the other one too, then you get your answer
9514 1404 393
Answer:
y = 3x -8
Step-by-step explanation:
We assume you want the tangent to the parabola y = x² -3x +1 at the given point. The slope is found using the derivative of the function at that point.
y' = 2x -3
At x=3, the slope is ...
y' = 2(3) -3 = 3
The equation of the line through point (3, 1) with a slope of 3 is ...
y -1 = 3(x -3) . . . . use the point-slope form of the equation for a line
y = 3x -9 +1 . . . . . eliminate parentheses, add 1
y = 3x -8