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riadik2000 [5.3K]
3 years ago
11

I need an answer pretty quickly.

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

I think it would be option 1

Step-by-step explanation:

Hope this is right and helpful

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Evaluate 8 - 4.7y - x, when y = -1 and x = 2.<br> A. -10.7<br> B. -9.7<br> C. 9.7<br> D. 10.7
seraphim [82]
It’s D, 10.7

8 - (4.7 x (-1)) - 2 = 10.7
5 0
3 years ago
The standard form of the equation for a quadratic function is, with he vertex of the graph of the function at the point (p,q). t
ludmilkaskok [199]

Answer:

p = ½ (x₁ + x₂)

q = a (x₁x₂ − ¼ (x₁ + x₂)²)

Step-by-step explanation:

y = a (x − x₁) (x − x₂)

Expand:

y = a (x² − x₁x − x₂x + x₁x₂)

y = a (x² − (x₁ + x₂)x + x₁x₂)

Distribute a to the first two terms:

y = a (x² − (x₁ + x₂)x) + ax₁x₂

Complete the square:

y = a (x² − (x₁ + x₂)x + ¼(x₁ + x₂)²) + ax₁x₂ − ¼ a(x₁ + x₂)²

y = a (x − ½ (x₁ + x₂))² + a (x₁x₂ − ¼ (x₁ + x₂)²)

Therefore:

p = ½ (x₁ + x₂)

q = a (x₁x₂ − ¼ (x₁ + x₂)²)

3 0
3 years ago
Bigideasmath.
ratelena [41]
The total number of calories for 18 cups of milk is 1620 calories.
If two cups of milk is 180 calories then divide 180/2 to find the unit rate.
Then multiply 90 by the number of cups (18) and then you get the total number of calories for that many drinks.
6 0
3 years ago
PLEASE HELP I AM SO CONFUSED
soldi70 [24.7K]

Answer:

Option D, 1

Step-by-step explanation:

<u>Step 1:  Determine what x1, x2, y1, y2 are</u>

Slope = \frac{y2 - y1}{x2-x1}

(x1, y1) is (2, 8)

(x2, y2) is (6, 12)

<u>Step 2:  Plug into the formula to get the slope</u>

Slope = \frac{y2 - y1}{x2-x1}

Slope = \frac{12 - 8}{6 - 2}

Slope = \frac{4}{4}

<em>Slope = 1</em>

<em />

Answer:  Option D, 1

5 0
3 years ago
Read 2 more answers
Find the value of y for which line a is parallel to line b.
alexdok [17]
Y+38°= 180 beacuse if a and b are parallel they are co interior angles. This means that they will at to 180.

y=180-38= 142°

Answer: 142°

Drew out some hopefully helpful pictures below. Hope they help! let me know if you still have any questions!

6 0
3 years ago
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