Answer:
(4,2)
Step-by-step explanation:
-3x+5y=-2
3x+7y=26
I will add the two equations to eliminate x
-3x+5y=-2
3x+7y=26
---------------------
0x + 12y = 24
Divide by 12
12y/12 = 24/12
y =2
Now find x
3x+7y =26
3x+7*2 =26
3x+14= 26
Subtract 14 from each side
3x+14-14 =26-14
3x= 12
Divide by 3
3x/3 =12/3
x=4
Answer:
Step-by-step explanation:
Given the simultaneous equation 2p - 3q = 4 and 3p + 2q = 9, to get the value of p and q we will use elimination method.
2p - 3q = 4 ...................... 1 * 3
3p + 2q = 9 ..................... 2 * 2
Multiplying equation 1 by 3 and 3 by 2:
6p - 9q = 12
6p + 4q = 18
Subtracting both equation
-9q-4q = 12-18
-13q = -6
q = -6/-13
q = 6/13
Substituting q = 6/13 into equation 2
2p - 3(6/13) = 4
2p - 18/13 = 4
2p = 4+18/13
2p = (52+18)/13
2p = 70/13
p = 70/26
p = 35/13
<em>Hence p = 35/13 and q = 6/13</em>
<em></em>
<em>b) </em>If if 223ₓ = 87 find x
Using the number base system and converting 223ₓ to base 2 will give us;
223ₓ = 2*x² + 2*x¹ + 3*x⁰
223ₓ = 2x²+2x+3
Substituting back into the equation, 2x²+2x+3 = 87
2x²+2x+3-87 = 0
2x²+2x-84 = 0
x²+x-42 = 0
On factorizing:
(x²+6x)-(7x-42) = 0
x(x+6)-7(x+6) = 0
(x+6)(x-7) = 0
x+6 = 0 and x-7 = 0
x = -6 and 7
<em>Hence the value of x is 7 (neglecting the negative value)</em>
Answer:
cool
Step-by-step explanation:
Answer:
A'(-1,-4)
B'(-5,-8)
C'(-5,-4)
D'(-4,-2)
Step-by-step explanation:
We have been given a graph of a quadrilateral and we are asked to find the coordinates of our quadrilateral after reflecting it across the x-axis.
We can see that coordinates of quadrilateral ABCD are:
A (-1,4),
B (-5,8),
C (-5,4),
D (-4,2).
Since we know that rule for reflecting an image across x-axis is . This means that y-coordinates of our given image will be negative.
So after reflecting our given quadrilateral across x-axis, coordinates will be:
Answer:
The missing angle is 109°