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9966 [12]
4 years ago
8

In ΔEFG, the measure of ∠G=90°, the measure of ∠F=23°, and FG = 31 feet. Find the length of GE to the nearest tenth of a foot.

Mathematics
1 answer:
alexira [117]4 years ago
6 0

Answer:

x=13.1587≈13.2 feet

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Angle α lies in quadrant II , and tan α = <img src="https://tex.z-dn.net/?f=-%5Cfrac%7B12%7D%7B5%7D" id="TexFormula1" title="-\f
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Since \alpha lies in quadrant II and \beta lies in quadrant IV, we expect \sin\alpha>0, \cos\alpha, and \sin\beta.

Recall the Pythagorean identities,

\sin^2x+\cos^2x=1\iff1+\cot^2x=\csc^2x\iff\tan^2x+1=\sec^2x

It follows that

\sec\alpha=\dfrac1{\cos\alpha}=-\sqrt{\tan^2\alpha+1}=-\dfrac{13}5\implies\cos\alpha=-\dfrac5{13}

\sin\alpha=\sqrt{1-\cos^2\alpha}=\dfrac{12}{13}

\sin\beta=-\sqrt{1-\cos^2\beta}=-\dfrac45

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\sin(\alpha+\beta)=\dfrac{12}{13}\dfrac35+\left(-\dfrac45\right)\left(-\dfrac5{13}\right)=\boxed{\dfrac{56}{65}}

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