What is the value of the summation ∑i=14(2i+6i2)
1 answer:
You need to know the following:
sigma(i) = 1/2 * i * (i+1)
sigma(i^2) = 1/6 * i * (i+1) * (2i+1)
Therefore, the answer should be 14( i(i+1) + i * (i+1) * (2i+1)) = 14i(i+1)(2i+2) = 28i(i+1)^2
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