40x^2 - 20x
(10x-5)(2*2+4x-4)
(10x-5)(4-4+4x)
(10x-5)(4x)
40x^2 - 20x
<span>let:
m1 = 2xy a
m2 = 2xy b
m3 = 2x2y c
since 2 and 3 have a common factor let b=2n
m1 = 2xy a
m2 = 2xy 2 n
m3 = 2x2y c
or simply
m1 = 2xy a
m2 = 2xy 2n
m3 = 2xy 2c
given that anc have no common factors</span>
Answer:
15 3/4t^2 + 5 1/4
Explanation:
h(t)=-16t^2+400
We can add 400 then - 64 and show as 8^2
= h(t)=-16t^2+400 - 8^2
But we also need to change 16t^2;
We divide 64 into 16 = 16/64 =0.25
and show 16t^2 changes by 0.25 = 1/4
15 3/4t^2 + 400-64
Can now look like
15 3/4t^2 + 5 1/4
As 5 1/4 = 64 x 5 1/4 = 336
A = 6
tn = a + (n - 1)d
t4 = 6 + 3d = 12
3d = 12 - 6 = 6
d = 6/3 = 2
f(n + 1) = f(n) + 2
Answer:
Yes
Step-by-step explanation:
For ease, let's multiply these by 10,000.
0.09 • 10,000 = 900.00 = 900
0.0003 • 10,000 = 3.00 = 3
900 is clearly greater than 3. Therefore, 0.09 is greater than 0.0003.
