Question

A survey of 100 people in New York City, NY found that.

Answer 1

Answer: 0.9

Step-by-step explanation:

$\mathrm{Total \ sample \ space \ =100 } \\\mathrm{Event \ A = \ taking \ subway \ each \ day} P(A)=0.85 Event B= taking taxi \because P(B)=0.6 P(A \cap B)=0.55$

$\begin{aligned}P(A \cup B) & \Rightarrow \text { Person taking either taxi/subway } \\&=P(A)+P(B)-P(A \cap B) \\&=(0.85-0.555)+(0.6-0.55)-0.55 \\&=1.45-0.55\\&\bf{=0.9} \end{aligned}$