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borishaifa [10]
3 years ago
6

What is the VERTEX of the quadratic y = 2

Mathematics
2 answers:
Viktor [21]3 years ago
8 0

Answer:

the vertex is located at (-4, 1)

Step-by-step explanation:

The vertex equation of a vertical parabola is

y = a(x - h)^2 + k

where (h, k) is the vertex.  

Comparing this to the given

y = 2(x + 4)² + 1, we see that the vertex is located at (-4, 1) and that the graph is stretched vertically by a factor of 2.

RSB [31]3 years ago
4 0

Answer:

The vertex is ( -4,1)

Step-by-step explanation:

The equation for a parabola can be written as

y = a( x-h)^2 +k  where ( h,k) is the vertex

y = 2 (x + 4)² + 1

Rewriting

y = 2 (x -  -4)² + 1

The vertex is ( -4,1)

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Angle 1 is 112°, 2 is 68°, 3 is 90°, 4 is also 90°, 5 is 22° and angle 6 is 158°

Step-by-step explanation:

To find angles 3 &4 and 2 &1, you subtract the measurement given in each intersection from 180 (all straight lines are 180) to find the other angle measurements. To find 5 I used the 4th angle and the 2nd angle to find the missing number out of 180 since all of the angles in a triangle have a sum of 180°. The missing angle was 22. You can use the angle measurement of #5 to find 6 like how I mentioned before about all straight lines equaling 180°. If this all sounds like mumbo-jumbo I can elaborate a little more in the comment section!

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3 years ago
Find f(b-2) if f(x) = x^2-6x+1
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent expression is ~

  • f(b - 2) =  {b}^{2}  - 10b + 17

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's evaluate f(b - 2) ~

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  • f(b - 2) = (b - 2) {}^{2}  -6 (b - 2) + 1

  • \mathcal{ {f(b - 2) =  {b}^{2}   +  2 {}^{2}  - (2 \times b \times 2) - 6b + 12}}

  • f(b - 2) =  {b}^{2}   + 4 - 4b - 6b + 12 + 1

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3 years ago
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