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borishaifa [10]
3 years ago
6

What is the VERTEX of the quadratic y = 2

Mathematics
2 answers:
Viktor [21]3 years ago
8 0

Answer:

the vertex is located at (-4, 1)

Step-by-step explanation:

The vertex equation of a vertical parabola is

y = a(x - h)^2 + k

where (h, k) is the vertex.  

Comparing this to the given

y = 2(x + 4)² + 1, we see that the vertex is located at (-4, 1) and that the graph is stretched vertically by a factor of 2.

RSB [31]3 years ago
4 0

Answer:

The vertex is ( -4,1)

Step-by-step explanation:

The equation for a parabola can be written as

y = a( x-h)^2 +k  where ( h,k) is the vertex

y = 2 (x + 4)² + 1

Rewriting

y = 2 (x -  -4)² + 1

The vertex is ( -4,1)

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2 years ago
I need help can I have how to do it and some work so I can do it.
tiny-mole [99]

Answer:

(-1,-2) OR x = -1 and y = -2

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so you would first multiply everything on y = -x -3 by 3 and get 3y = -3x -9

so then you would add 3y = -3x -9 to y = 3x + 1 (<u> to eliminate the x</u> )which would be 4y = -8 then divide by 4 and get  <u><em>y = -2</em></u>

then you plug in y = -2 into any one of the equations but to make it easier i am going to plug it into y = -x -3 so now it would be -2 = -x - 3 then, add 2 to both sides which would be 0 = -x -1 then add 1 to both side 1 = -x then multiply both sides by -1 and get <u><em>x = -1</em></u>

<u><em>SO your answer would be </em></u> (-1,-2) OR x = -1 and y = -2 ( both of them are correct but it depends on what the teacher taught you)

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