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love history [14]
3 years ago
6

Can u pls help me with this question asap ​

Mathematics
1 answer:
alexdok [17]3 years ago
6 0
Between 3 and 4 cups.

Let’s find 87% of 4.
(4)(0.87)= 3.48

So in 4 cups of milk, there is 3.48 cups of water, which is between 3 and 4 cups.
You might be interested in
A college with a graduating class of 4000 students in the year 2010 predicts that its graduating class will grow 5% per year.
anastassius [24]

Hello,

u_0=4000\\u_1=4000*1.05 (for\ year\ 2011)\\\\u_n=4000*1.05^n\\So:\\year\ 2017: u_7=4000*1.05^7=5628,401690625\ \approx{5628}

7 0
3 years ago
Perpendicular to y=1/2-1, x-intercept at4
AlexFokin [52]

Answer:

it would be Y= -2x+4

Step-by-step explanation:

To begin, we know that the b value is 4, because that is the x-intercept that is information given, so we can atomatically put that in.

Next we need to find the m value, which can be found by knowing the rules of a perpendicular eqution. to change it you must change the 1/2 and flip the equation and change the signs

soooooo  1/2 would change into 2/1   which is 2 and we would addd the negative sign so

Y=-2x+4

8 0
4 years ago
Read 2 more answers
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
14.7 ml and a mass of 22.8 g
aliya0001 [1]

The density of the liquid is 1.55 g/mL.

Given the following data:

Mass of liquid = 22.8 grams

Volume of liquid = 14.7 mL

To find the density (unknown) of the liquid:

Density is mass all over the volume of a substance or an object.  Thus, density is mass per unit volume of an object.

Mathematically, the density of a substance is given by the formula;

Substituting the values into the formula, we have;

Density = 1.55 g/mL

Therefore, the density of the liquid is 1.55 g/mL.

Read more: brainly.com/question/18320053

5 0
1 year ago
Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
3 years ago
Read 2 more answers
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