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Aleks04 [339]
3 years ago
13

Urgente!!! Doy 20 puntos

Mathematics
1 answer:
andre [41]3 years ago
4 0

Answer:

  1. 7
  2. 4
  3. -7, 0, +9

Step-by-step explanation:

Hope this helps

You might be interested in
What is the scientific notation of 130400000)
kompoz [17]
That would be 1.304*10 exponent 8 right?!?!
7 0
3 years ago
Read 2 more answers
There were 450 tickets purchased for a major league baseball game. the general admission tickets cost $6.50 and the upper box ti
lidiya [134]

Answer:

Step-by-step explanation:

So you first pretend they were all the general admission tickets which is

450x6.50$=2925$ So the number is 4237.50$-2925$=1312.50$ away from the actual price. The price difference between the two is 10.00$-6.50$= 3.50$

Then you put the total price difference 1312.50$ and divide by 3.50$ then you get the amount of upper box tickets. 1312.50$/3.50$=375( Amount of Upper box. So now you know how many upper box were bought. You take it away from 450 tickets sold. 450-375=75

375x10=3750$

75x6.5=487.5$

3750$+487.5$=4237.5$

Hope that helped you!

5 0
4 years ago
I’m new to this app so I don’t know how to give more points but I would appreciate it if you could help
faust18 [17]

Hi! The answer would be all real numbers!

Hope this helps! :)

8 0
3 years ago
Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
3 years ago
PLEASE HELP I NEED SOMEONE TO GET POINTS.
Nostrana [21]

Answer:

ok

Step-by-step explanation:

5 0
3 years ago
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