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MakcuM [25]
3 years ago
7

5/8 of the prizes at the giant spin were dolls if their were 64 prizes how many prizes were not dolls ?

Mathematics
1 answer:
denis23 [38]3 years ago
4 0
If 5/8 of the prizes were dolls, then 3/8 of the prizes were not dolls.

3/8 of 64......" of " means multiply
3/8 *  64 = 192/8 = 24 were not dolls <==
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If the code for CAB is DEK, what is the code for BED?
snow_tiger [21]

Answer:

CIM

Step-by-step explanation:

C is the 3rd letter of the alphabet, A is the 1st, and B is the 2nd.

CAB = 3,1,2

Repeating for DEK:

DEK = 4,5,11

Comparing:

4−3 = 1

5−1 = 4

11−2 = 9

BED = 2,5,4, so adding the corresponding numbers:

2+1 = 3

5+4 = 9

4+9 = 13

So the code is CIM.

7 0
3 years ago
Gabriella made 36 cookies. She gave away 28 cookies. Use the equation 28 + c = 36 to find c, the number of cookies she kept.
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2 years ago
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5 0
2 years ago
Total profit P is the difference between total revenue R and total cost C. Given the following​ total-revenue and​ total-cost fu
gavmur [86]

Answer:

The profit function is:

P(x)=-x^2+1280x-3300

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Step-by-step explanation:

The revenue function is:

R(x)=1300x-x^2

And the cost function is:

C(x)=3300+20x

Then the total profit function will be:

P(x)=R(x)-C(x)=(1300x-x^2)-(3300+20x)=-x^2+1280x-3300

This is a quadratic function.

Therefore, the maximum value of the total profit will occur at its vertex point.

The vertex of a quadratic is given by:

\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)

In this case, a = -1, b = 1280, and c = -3300.

Then the point at which the maximum profit occurs is at:

\displaystyle x=-\frac{1280}{2(-1)}=640

And the maximum profit will be:

P(640)=-(640)^2+1280(640)-3300=406300

5 0
3 years ago
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