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MakcuM [25]
3 years ago
7

5/8 of the prizes at the giant spin were dolls if their were 64 prizes how many prizes were not dolls ?

Mathematics
1 answer:
denis23 [38]3 years ago
4 0
If 5/8 of the prizes were dolls, then 3/8 of the prizes were not dolls.

3/8 of 64......" of " means multiply
3/8 *  64 = 192/8 = 24 were not dolls <==
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Chloe wants to buy monitor for her bedroom the height of the monitor is 18 inches in the width is 16 inches calculate the diagon
Akimi4 [234]
Equation: a^2 + b^2 = c^2

18^2 + 16^2 = c^2

324 + 256 = c^2

C^2 = square root 580

Square root 580 reduces to 2 square root 145.

As a decimal that is: 24.08

Rounded to the nearest tenth: 24 inches.

I hope this helps! If it does please offer me the brainiest!
3 0
3 years ago
(question 4 only plz)
Hatshy [7]
#4
White block(s) = 2
Red block(s) = 1
Purple block(s) = 3
Total = 2 +1 + 3 = 6 blocks

a) P(white) = \frac{2}{6} = \frac{1}{3}
    P(red) = \frac{1}{6}
    P(purple) = \frac{3}{6} =  \frac{1}{2}

b)Not white block:
   1 - \frac{1}{3}   OR   \frac{1}{2} + \frac{1}{6}
    \frac{2}{3}                 \frac{2}{3}
Because, when they say no white blocks, we simply do not count them and add the rest to find that probability without white blocks.

c) The probability stays the same: lets say now we have
4 white blocks, 2 red, and 6 purple, total will be 12

P(white)=\frac{4}{12} which is still \frac{1}{3}

d) We get two more blocks in the numerator: lets say we have 4 white blocks, 3 red, 5 purple (after adding 2 of each color), total will be 12

P(purple)=\frac{5}{12}
(im not quite sure if my explanation here helps you though)

e) 1 more of white and purple, 5 more of red
  white = 3, purple = 4, red = 6, total = 12
(you can either add 2 to white or purple but make sure you add 5 of red)

P(red)=\frac{6}{12} = \frac{1}{2}
  


5 0
3 years ago
Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
3 years ago
Read 2 more answers
The box plot was created by using which pieces of data?<br> 1<br> 50<br> 75<br> 100<br> 125
VikaD [51]

Answer:

50,75,and 100 there's supposed to be a 20 too but it's not there but oh well

4 0
3 years ago
For what value of x does 3^4x – 27x-3?
AveGali [126]

Answer:

x=0,05555555... or x = 3/54 or x= 1/18

Step-by-step explanation:

81x-27x-3

54x=3

8 0
3 years ago
Read 2 more answers
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