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sesenic [268]
3 years ago
11

A mint produces 150,000 souvenir coins each year. In a random sample of 400 coins, 3 have a misprint. Predict the number of coin

s that will have misprints in a year.
Mathematics
1 answer:
Tema [17]3 years ago
5 0
150,000 / 400 = 375. 375(3)= 1,125 misprints per year. hope this helps!
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C.P.=Rs 400, LOSS=5%, S.P=Rs X, S.P.=C.P.-5% OF C.P, FIND S.P. (STEP BY STEP PLZ)​
balu736 [363]

s.p. = c.p. \times 5\% \\ or \: x = 400 \times 5 \div 100 \\ or \: x = 4 \times 5 = 20 \\

6 0
3 years ago
Mary travelled y meters from point A to point B at an average speed of 4 m/s. She continued
Rus_ich [418]

Answer: dont know

Step-by-step explanation:

6 0
3 years ago
Factor completely 36a 2 - 24a + 4
stira [4]
4<span>(9<span>a2</span>−6a+1<span>)
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3 years ago
Click here What is the average rate of change for this exponential function for the interval from x=2 to x = 4? 15 10 -5 5 10 O
Triss [41]

Answer:

c. 6

Step-by-step explanation:

Given

See attachment for graph

Required

Average rate of change

This is calculated as:

Rate = \frac{f(b) - f(a)}{b - a}

Where

(a,b) = (2,4)

So, we have:

Rate = \frac{f(4) - f(2)}{4 - 2}

Rate = \frac{f(4) - f(2)}{2}

Using the attached graph, we have:

f(2) = 4

f(4) = 16

So, we have:

Rate = \frac{16- 4}{2}

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4 0
3 years ago
Which equation will solve the following word problem? One small pitcher and one large pitcher can hold 12 cups of water. If the
Inessa [10]

Answer:

Option (1).

Step-by-step explanation:

Amount of water hold by both the pitchers (Large + small) = 12 cups

Let the small pitcher holds the water = S cups

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Total amount water hold by both = S + 2S

Equation for this situation will be,

S + 2S = 12

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7 0
3 years ago
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