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Slav-nsk [51]
3 years ago
11

How is -25 a rational number?​

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

because it can be expressed by a quotient

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Please help I need the answe pleaseeeeeeee
balandron [24]

Step-by-step explanation:

d^3=d*d*d=10*10*10=1000

450=c*1000

450/1000=c

9/20=c

8 0
3 years ago
The random variable X has the following probability mass function.X -1 0 2 6 7P(x) 0.3 0.1 0.3 0.2 0.1Answer the next 4 question
olga2289 [7]

Answer:

Step-by-step explanation:

Given that X has the following pdf.

x -1 0 2 6 7 Total

P(X) 0.3 0.1 0.3 0.2 0.1 1

xP(X) -0.3 0 0.6 1.2 0.7 2.2

x^2P(X) 0.3 0 1.2 7.2 4.9 13.6

     

Var(x) 13.6-2.2^2  8.76    

Std dev   2.959729717    

5) P( -1 < X ≤ 2) = P(0)+P(2)\\= 0.1+0.3=0.4

6. Find the cumulative distribution function F(x) and calculate F(3.2) =

x -1 0 2 6 7

P(X) 0.3 0.1 0.3 0.2 0.1

F(x) 0.3 0.4 0.7 0.9 1

F(3.2) = P(X<3.2) = ___F(X<6) = 0.7__________

7. E(X) = ______2.2_____

8. Var(X) = ____8.76______

3 0
3 years ago
The measure ∠BQS of is 80°. What is the m∠NQS? 42° 48° 128° 32°
fomenos

Answer:

m<NQS = 32°

Step-by-step explanation:

Given:

m<BQS = 80°

m<BQN = 48°

Required:

m<NQS

SOLUTION:

Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.

Therefore:

m<BQN + m<NQS = m<BQS (angle addition postulate)

48° + m<NQS = 80° (substitution)

m<NQS = 80 - 48° (Subtraction of 48 from each side)

m<NQS = 32°

3 0
3 years ago
Read 2 more answers
3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl
riadik2000 [5.3K]

Elimination Method

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}

If we multiply the equation 3 by (-1) we obtain this:

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\  \end{gathered}

2. We can replace this value of X in the 1st and 2nd equations

\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}

3. If we simplify:

\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}

4. We can obtain Y from this two equations:

\begin{gathered} Y=-\frac{-12Z+58}{9} \\  \end{gathered}

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}

6. If we simplify, we obtain:

X=\frac{-3Z+7}{9}

7. In conclusion, we obtain that

(X,Y,Z) =

(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)

8 0
1 year ago
How do I solve this?
expeople1 [14]

Answer:

4.5

Step-by-step explanation:

The formula for solving area in parallelograms is base x height.

The base is 2.5 and the height is 1.8

2.5x1.8=4.5

4 0
3 years ago
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