Help me please,Thanks

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

6 0

I think the answer is 4 because you have to count all the numbers before the 3rd marking. Also count the actual 3rd marking.

Sedaia [141]3 years ago

3 0

I believe the answer would be 3 actually. The question asks how many gained "fewer" than 3 pounds. In math, there is inclusive and exclusive. Inclusive meaning that includes the number starting or ending number on the number line and exclusive meaning it does not include. Questions will always clearly state when an inclusive answer is required. Therefore the question would have asked "how many dogs gained 3 or fewer pounds." Since this is not the case the answer should exclude 3 and therefore be 3 dogs.

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Solve the equation 4x^2 + 24x + 13 = 2x^2+ 6x to the nearest tenth.

Licemer1 [7]

Answer:

-0.8 and -8.2

Step-by-step explanation:

To solve a quadratic you first need to have one side of the equation equal to zero (because x-intercepts are when y is zero).

4x^2 + 24x + 13 = 2x^2 + 6x

2x^2 + 18x + 13 = 0

Then you can use the quadratic formula to solve for x. You will then come to

-18 ± sqrt(220) / 4

This will simplify out (rounding to the nearest tenth) to -0.8 and -8.2

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3 years ago

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3 years ago

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Explain how you could write a quadratic function in factored form that would have a vertex with an x-coordinate of 3 and two dis

skad [1K]

<span>The definition of quadratic function is given by:

</span> $(1) \ f(x)=ax^{2}+bx+c \\ \\ where \ a, b, c \ are \ real \ values$ <span>

So the problem asks for two conditions:

<em>1. Write the quadratic function in factored form. </em>
<em>2. The vertex has an x-coordinate of 3.</em>

Then the equation (1) must be written as follows:

</span> $f(x)=(x-m)(x-n) \\ \\ where \ m \ and \ n \ are \ the \ roots$ <span>

To satisfy the two conditions:

$\frac{m+n}{2}=3$

So we are free to choose the value of one root, say:

$m=1$

Thus:

$n=6-1=5$

Finally, the answer is:

$f(x)=(x-1)(x-5)$

The graph of this function is shown in the figure below.</span>