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3 years ago

Help me please,Thanks

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

6 0

I think the answer is 4 because you have to count all the numbers before the 3rd marking. Also count the actual 3rd marking.

Sedaia [141]3 years ago

3 0

I believe the answer would be 3 actually. The question asks how many gained "fewer" than 3 pounds. In math, there is inclusive and exclusive. Inclusive meaning that includes the number starting or ending number on the number line and exclusive meaning it does not include. Questions will always clearly state when an inclusive answer is required. Therefore the question would have asked "how many dogs gained 3 or fewer pounds." Since this is not the case the answer should exclude 3 and therefore be 3 dogs.

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A function is shown f(x) = 2/3x +3 what is the value of f (6)?

Katena32 [7]

Answer:

The answer is 28/9

Step-by-step explanation:

Step one

Given information

We are given that the function is

$f(x) = 2/3x +3$

And we are expected to find f(6), that is substitute the value of x with 6

Step two:

$f(6)= 2/3(6)+3\\\\f(6)=2/18+3\\\\f(6)=1/9+3\\\\f(6)=1+27/9\\\\f(6)= 28/9$

5 0

2 years ago

Choose a random number between 1 and 25. What is the probability that it is an even number

CaHeK987 [17]

Answer:

6/25

Step-by-step explanation:

its a probability out of all the odd numbers such as 1,3,5,7,9,11,13,15,17,19,21,23,25

3 0

3 years ago

Peeeeeeeeeeeeeeeeez help

Studentka2010 [4]

Answer:

no solution is ur right answer

Step-by-step explanation:

mark ‼️ it brainliest if it helps you ❤️

3 0

3 years ago

Read 2 more answers

Due tomorrow please help :)

coldgirl [10]

Okay, so your first one, number six. You have two shapes there, a cone and a circle. Now you have a full cone and a half of a circle. Let's start with the cone. The formula for the volume of a cone is πr²h/3. You have your height, that is 12, so get your paper out and plug that in. H = 12. Now, your radius is where it gets a bit tricky. Have you ever heard of the Pythagorean theorem? It's a²+b²=c². Look at the cone, but look at it like it's a two-dimensional shape. You see the triangle in the middle, ignore the rest and pretend it's only that triangle. You now have a right triangle, You know your height is 12, and by looking at the triangle adjacent to it, and know it's equal, you know that your hypotenuse (the longest side of your triangle) is 15. So plug that into the Pythagorean theorem. Now you have 12²+b²=15². Use algebra to work that out, and you're left with 9. So your radius is 9. Now plug that into your volume of a cone equation. The volume of the cone is about 1017.88. Now find the circle or sphere. The formula is 4/3πr³. Just plug in your radius and get your answer, which is 3053.63. Now cut that in half, as you've only got half a circle. Now you've got 1526.82. Now add that to the volume of your cone, and you've got your final answer. 2544.7, or about that. I used π on a calc, and not 3.14, so it might be a little different.

Do you think you can do the next one? Just look at your triangle in there. You've already got one side and a hypotenuse, so plug it into the Pythagorean theorem and get your last side. Then look at the little marks on there and you can see if places are the same. If you need help with it don't hesitate to ask. I'm staying up all night anyway. Homeschooled and behind, so I'm not going anywhere.

7 0

2 years ago

5x+7y=31 2x+4y=16 Which of the following systems could be used to solve the given system of equations by the addition method? 10

Pani-rosa [81]

Equation 1: $5x+7y=31$
Equation 2: $2x+4y=16$

We can either use the 'elimination' method or the 'substitution' method to solve this simultaneous equation.

In some cases one method is easier to use than the other. For this one, it would be easier to use the elimination method

We need to eliminate either the 'x' or the 'y' to begin with. Say we want to eliminate the 'x' terms, then the next step is to make the constant the same

Equation 1: the constant of 'x' is 5
Equation 2: the constant of 'x' is 2

To make the two constants the same, think of common multiple. The lowest common multiple for 5 and 2 is 10

Equation 1: Multiply all terms by 2 to achieve 10x
Equation 2: Multiply all terms by 5 to achieve 10x

Equation 1: $10x+14y=62$
Equation 2: $10x+20y=80$

Once the constant of 'x' is the same, then we can start the elimination process. Since our aim is to eliminate, one of the 'x' need to be in negative form. We can either multiply Equation 1 or Equation 2 by (-1)

Equation 1: -10x - 14y = -62
Equation 2: 10x + 20y = 80

Hence the correct answer is: Third option

3 0

3 years ago