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Karolina [17]
4 years ago
5

How do you write add 4 to n then multiply by 5 in algebraic expression

Mathematics
1 answer:
irina [24]4 years ago
5 0
Here is the anwer to your question ,
n+4•5
You might be interested in
. What tool can you use to improve your health?
Angelina_Jolie [31]

Answer:

G. All of these answers

Step-by-step explanation:

It would be all of them because some have to do with exercise and the others have to do with a plan for dieting and exercising.

6 0
3 years ago
Joni’s hair is 13 inches long and grows at an average rate of ⅔ in per month. Her friend Kate’s hair is 16 inches long and grows
ale4655 [162]

Answer:

18

Step-by-step explanation:

13 + (⅔)t = 16 + (½)t

(⅔ - ½)t = 3

t/6 = 3

t = 18

6 0
4 years ago
Reduce the following fraction to lowest terms: 16/20
UNO [17]

4/5 is the answer to reduce to the lowest of 16/20


5 0
4 years ago
Add parentheses to the equation below so that x = 90. 3 + 2^2 /4 - 10 = x
8090 [49]

Answer:

(3+2)²*4-10=x

Step-by-step explanation:

If it was a typo and is actually times 4, not divided by 4, then here is the answer:

(3+2)²*4-10=x

5²*4-10=x

25*4-10=x

100-10=x

90=x

If it actually was divided by 4, I don’t see any way it can be done.

7 0
3 years ago
Find the common ratio of the geometric sequence.
Kay [80]

Answer:

The common ratio is \frac{1}{x^4}

Step-by-step explanation:

Geometric sequence:A geometric sequence is a sequence in which the ratio of any term to the preceding term of that term is always constant.

Common ratio: The ratio of any term to the  preceding term of that term.

The n^{th} term of a geometric sequence is represented by  a_n=ar^{n-1}.

The 1^{st} term of the sequence = a.

The sum of first n term is

S_n=\frac{a(1-r^n)}{1-r}

The common ratio = r.

Given geometric sequence,

\frac{1}{x^{10}} , \frac{1}{x^{14}}, \frac{1}{x^{18}},\frac{1}{x^{22}} ........

The common ratio is

=\frac{\textrm{second term}}{\textrm{first term}}

=\frac{\frac{1}{x^{14}}}{\frac{1}{x^{10}}}

=\frac{x^{10}}{x^{14}}

=\frac{1}{x^4}

6 0
4 years ago
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