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aliya0001 [1]
3 years ago
13

Trevor paints 1/6 of a fence surrounding his farm each day how many days will it take him to paint 3/4of the fence

Mathematics
1 answer:
natali 33 [55]3 years ago
6 0
4 1/2 days. I first made the fractions have an equal denominator(24). Then make the numerator equal up. (1/6 to 4/24) (3/4 to 18/24). Then, I counted (by 4/24) until I got to 18/24.
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Please help me with number ten and twelve
jasenka [17]

Answer: 93,\ 34^{\circ}

Step-by-step explanation:

Given

For figure (i) both triangles are congruent

\therefore 8x-27=4x+33\\\Rightarrow 8x-4x=33+27\\\Rightarrow 4x=60\\\Rightarrow x=15

\Rightarrow PQ=8x-27\\\Rightarrow PQ=93

For figure (ii)

Two triangles WXZ and WZY are congruent

\therefore 9x-28=5x-8\\\Rightarrow 4x=20\\\Rightarrow x=5^{\circ}\\\Rightarrow \angle YWX=2(9x-28)\\\Rightarrow \angle YWX=2(17)\\\Rightarrow \angle YWX=34^{\circ}

5 0
2 years ago
Divide 735 in the ratio 3:2
Irina18 [472]
First add the 2 numbers in the ratio:

3+2 = 5

divide the 735 by 5:

735 / 5 = 147

now multiply 147 by 3 and then by 2 and that will be the ratios:

147 * 3 = 441

147 * 2 = 294
6 0
3 years ago
In Sakura's garden, for every 5 red flowers, there are 10 yellow flowers. There are 75 total red and yellow flowers. How many re
sweet [91]

Answer: there are 25 red flowers in Sakura's garden.

Step-by-step explanation:

In Sakura's garden, for every 5 red flowers, there are 10 yellow flowers. This means that if there are 10 red flowers, there would be 20 yellow flowers. if there are 20 red flowers, there would be 40 yellow flowers. Therefore, the ratio of red flowers to yellow flowers in the garden is

5/10 = 10/20 £= 20/40 = 1/2 = 1:2

Total ratio = 2 + 1 = 3

If there are 75 total red and yellow flowers, then the total number of red flowers are in Sakura's garden would be

1/3 × 75 = 25

8 0
3 years ago
What is (9p - 2) - (6p - 8)
Bezzdna [24]
The answer is 3p+6 gggghhnbhjjn
3 0
3 years ago
Read 2 more answers
What is the sum of the polynomials? (9x4−13x3−x−7)+(7x3−2x+1) A.) −6x^6+9x^4−3x^2−6 B.)−6x^6+9x^4−x−8 C.)9x^4−6x^3−x−8 D.)9x^4−6
irinina [24]
(9x^4-13x^3-x-7)+(7x^3-2x+1)=
9x^4-13x^3-x-7+7x^3-2x+1=
9x^4+(-13+7)x^3+(-1-2)x-7+1=
9x^4+(-6)x^3+(-3)x-6=
9x^4-6x^3-3x-6

Answer: Option <span>D.)9x^4−6x^3−3x−6</span>
5 0
3 years ago
Read 2 more answers
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