703.4 cmsquare
Hope it helps
In this attached picture, we can prove that triangles AOB and COD are congruent. ∠CDO and ∠ABO are equal because they are alternate angles. Similarly, ∠OAB and ∠OCD are equal because they are alternate angles, as well. We have a rectangle and in the rectangle, opposite sides are equal; AB = CD. Then, because of Angle-SIde-Angle principle, we can say that triangles AOB and COD are equal. If triangles are congruent, then OD = OB and OC = AO. Applying congruency to the triangles ACD and BCD, we can see that these triangles are also congruent. It means that the diagonals are equal. Since, OD = OB and OC = AO, it proves that the point O simultaneously is the midpoint and intersection point for the diagonals.
Answer:
<em>(d) sin G = 15/17</em>
Step-by-step explanation:
For angle G, opp = 15, adj = 8, hyp = 17.
cos G = adj/hyp = 8/17
sin G = opp/hyp = 15/17
Answer: (d) sin G = 15/17
Answer:
huh ano yan huhu paki ayos ng sagot
Step-by-step explanation:
hahahhaa
Answer:
32
Step-by-step explanation:
If <em>y</em> is 2 times as much as <em>x</em>, then 1 = 2
5 x 3 = 15 + 1 = 16
10 x 3 = 30 + 2 = 32, or 16 x 2 = 32
Please tell me if I'm wrong.