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3 years ago

Nash and two of his friends are sharing some leftover lasagna. If 2/5 of the lasagna is left, how much will each of them get?

Mathematics

1 answer:

Leto [7]3 years ago

5 0

Each one of them will get $\frac{2}{15}$ of leftover lasagna.

Step-by-step explanation:

Amount of leftover lasagna = $\frac{2}{5}$

As Nash and two friends will share, the lasagna will be divided into three parts, therefore, we will divide the leftover amount by 3.

$\frac{1}{3}$ is also considered as divided by three.

Therefore,

Share of one person = $\frac{2}{5}*\frac{1}{3}$

Share of one person = $\frac{2}{15}$

Each one of them will get $\frac{2}{15}$ of leftover lasagna.

Keywords: fraction, division

Learn more about fractions at:

#LearnwithBrainly

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Angles in circle solve for each variable

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Answer:

Step-by-step explanation:

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3 years ago

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago

Ember has $80 to spend on clothes. She wants to buy a pair of jeans that cost $35 and spend the rest on t-shirts. Each T-shirt c

ICE Princess25 [194]

Answer:

she can buy 9 shirts

Step-by-step explanation:

80-35=45

45÷5=9

plz mark brainlyest

8 0

3 years ago

Read 2 more answers

If the hikers want to share the fruit evenly , how many Leicester should each person receive?

sveticcg [70]

An even amount each
EXAMLEE;there are 4 potatoes and 2 people they want to split it evenly so 4potatoes/2people
4 divided by 2
they both get 2 potatoes.
stupid example but hope it helps

6 0

3 years ago

What is 50,000 times 10 to the 15th

Misha Larkins [42]

Remember property of exponents
$(x^m)(x^n)=x^{m+n}$
add exponents of same base

ok so

50,000 is 5 times 10^4

so

50000 times 10^15=
5 times 10^4 times 10^15=
5 times $10^{4+15}$ =
5 times 10^19

8 0

3 years ago