All categories

2 years ago

One more i need help with plz answer I need it done by today

Mathematics

2 answers:

polet [3.4K]2 years ago

5 0

Answer:187.5 inches.

Step-by-step explanation:

25 / 2 = x / 15

25 = 2x / 15

15(25) = 2x

375 = 2x

187.5 = x

The actual car is 187.5 inches.

Mrrafil [7]2 years ago

4 0

Answer:

x=200

Step-by-step explanation:

Step 1: Cross-multiply.

2 /25 = 16 /x

2x=400

Step 2:

Divide both by 2

answer should be x=200

You might be interested in

An article suggests that a poisson process can be used to represent the occurrence of structural loads over time. suppose the me

kirill115 [55]

Answer:

a) $\lambda_1 = 2*2 = 4$

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

$X(2) \sim Poi (4)$

And the expected value is $E(X) = \lambda =4$

So we expect 4 number of loads in the 2 year period.

b) $P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]$

$P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]$

And we got: $P(X(2) >6) =1-0.889=0.111$

c) $e^{-2t} \leq 2$

We can apply natural log in both sides and we got:

$-2t \leq ln(0.2)$

If we multiply by -1 both sides of the inequality we have:

$2t \geq -ln(0.2)$

And if we divide both sides by 2 we got:

$t \geq \frac{-ln(0.2)}{2}$

$t \geq 0.8047$

And then we can conclude that the time period with any load would be 0.8047 years.

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution"

Solution to the problem

Let X our random variable who represent the "occurrence of structural loads over time"

For this case we have the value for the mean given $\mu = 0.5$ and we can solve for the parameter $\lambda$ like this:

$\frac{1}{\lambda} = 0.5$

$\lambda =2$

So then $X(t) \sim Poi (\lambda t)$

X follows a Poisson process

Part a

For this case since we are interested in the number of loads in a 2 year period the new rate would be given by:

$\lambda_1 = 2*2 = 4$

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

$X(2) \sim Poi (4)$

And the expected value is $E(X) = \lambda =4$

So we expect 4 number of loads in the 2 year period.

Part b

For this case we want the following probability:

$P(X(2) >6)$

And we can use the complement rule like this

$P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]$

And we can solve this like this using the masss function:

$P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]$

And we got: $P(X(2) >6) =1-0.889=0.111$

Part c

For this case we know that the arrival time follows an exponential distribution and let T the random variable:

$T \sim Exp(\lambda=2)$

The probability of no arrival during a period of duration t is given by:

$f(T) = e^{-\lambda t}$

And we want to find a value of t who satisfy this:

$e^{-2t} \leq 2$

We can apply natural log in both sides and we got:

$-2t \leq ln(0.2)$

If we multiply by -1 both sides of the inequality we have:

$2t \geq -ln(0.2)$

And if we divide both sides by 2 we got:

$t \geq \frac{-ln(0.2)}{2}$

$t \geq 0.8047$

And then we can conclude that the time period with any load would be 0.8047 years.

3 0

2 years ago

SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER TO COMPLETE THIS! NO LINKS OR

slega [8]

Answer:

We must use the formula b x h/2 12 x 8/2 = 48

A=48

We must use the formula 1/2a root c squared - a squared

Solving and substituing will get you 35.78

We must divide 81 by 2 to get 9. Since this is a square, all sides will be 9. Then, we must add 9 four times to get 36 cm as our perimeter

B) If we draw the square with a diagonal line, we can understand that the diagonal line (hypotenus) is s root 2.

3) The formula for this area of a triangle is h x b/2. We must substitute the numbers to get our answer:

h x b /2 = 10 x 20/2 = 200/2 = 100

AREA IS 100cm squared

Step-by-step explanation:

5 0

2 years ago

To join a local square dancing group, Jan has to pay a $100 sign-up fee plus $25 dollars per month. Write an equation for the co

NemiM [27]

Answer:

y = 25x+100

Step-by-step explanation: You are paying 25$ times how many months he stayed there, plus a 100 dollar sign up fee, so y = 25 dollars per month, plus 100 dollars.

4 0

2 years ago

Can someone Please help.

Nastasia [14]

Since it is mid-way you would multiply it by 2 so, 8x2=16
Your answer is 16.
Hope I helped <3

4 0

2 years ago

In six grade class, 3/7 of the students are boys, and 5/8 of these boys are in Ms. Jones’ class. What fraction of the entire six

Damm [24]

Think of the entire population of 6th graders here. 3/7 are boys and 4/7 are girls. 5/8 of these boys are in Ms. Jones' class; that fraction would be (5/8)(3/7), or 15/56. This 15/56 represents the fraction of the entire sixth grade class who are in Ms. Jones' class.

8 0

2 years ago

Read 2 more answers