C=πd where C=circumference, π=the constant pi, and d=diamter
d=C/π and since we are told that C=9π
d=9π/π
d=9
Answer:
Step-by-step explanation:
Xét tam giác DAB có: P là trung điểm AD, M là trung điểm AB
=> MP là đường trung bình của tam giác DAB => MP//BD và MP=
BD (1)
Xét tam giác DBC có: N là trung điểm DC, Q là trung điểm BC
=> QN là đường trung bình của tam giác DBC => QN//BD và QN=
BD (2)
Từ (1) và (2) => vecto MP song song cùng chiều với vecto QN
và độ dài MP = độ dài QN =
BD
=> vecto MP = vecto QN
Tương tự xét các tam giác DAC và tam giác ABC => vecto MQ = vecto PN
To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!
![\boxed{ \sf \: area \: of \: square =side ^{2} }](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Csf%20%5C%3A%20area%20%5C%3A%20of%20%5C%3A%20square%20%3Dside%20%5E%7B2%7D%20%20%7D)
![\rm \implies \: area = 3 ^{2}](https://tex.z-dn.net/?f=%20%5Crm%20%5Cimplies%20%5C%3A%20area%20%3D%203%20%5E%7B2%7D%20)
![\rm \implies9](https://tex.z-dn.net/?f=%20%5Crm%20%5Cimplies9)
<em>Thus, The area of 1st square is 9m²...</em>
- The area of second square will be also 9m², because the sides of both squares are equal.
<h3>
Now area of the reactangle⤵️</h3>
- Length = 6m
- Breadth = 7+3=10m
![\sf \: area \: of \: rectangle = length \times breadtg](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20area%20%5C%3A%20of%20%5C%3A%20rectangle%20%3D%20length%20%5Ctimes%20breadtg)
![\tt \dashrightarrow \: area = 10 \times 3](https://tex.z-dn.net/?f=%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%20area%20%3D%2010%20%5Ctimes%203)
![\tt \dashrightarrow \: area = 30m ^{2}](https://tex.z-dn.net/?f=%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%20area%20%3D%2030m%20%5E%7B2%7D%20)
<em>Thus, The area of rectangle is 30m²....</em>
- Now, Add area of all the figures to get the total area.
![\bf \:total \: area = 9 + 9 + 30 \\ \bf= 48m {}^{2}](https://tex.z-dn.net/?f=%20%5Cbf%20%5C%3Atotal%20%5C%3A%20area%20%3D%209%20%2B%209%20%2B%2030%20%5C%5C%20%20%20%5Cbf%3D%2048m%20%7B%7D%5E%7B2%7D%20)
<h3><em>Therefore, The total area of the composite figure is 48m²...~</em></h3>
Answer:
-u+5
Step-by-step explanation:
plz mark as brainliest
Answer:
54 Pounds
Step-by-step explanation:
We know that they start off with 67.5 pounds of sugar and they need to reduce it by 20%. We also know from the problem that we want to know the MAXIMUM amount of sugar consumed by each track member.
The typical high school student consumes about 67.5 pounds of sugar per year. That is our first piece of the problem
67.5
We now know that 20% of it needs to be reduced. This means that we can multiply it by 0.8 because that is 20% less than 100% of the sugar.
67.5 x 0.8
This leads the answer to be 54 Pounds
Hope this helped :D