It’s b) an =-125(-^2/5)^n
I think C Tell me if I’m wrong
Answer:
4
Step-by-step explanation:
You have 0.44
0 is in the ones place
4 is in the tenths place (0.4)
And the other 4 is in the hundredths place (0.04)
Check the forward differences of the sequence.
If
, then let
be the sequence of first-order differences of
. That is, for n ≥ 1,

so that
.
Let
be the sequence of differences of
,

and we see that this is a constant sequence,
. In other words,
is an arithmetic sequence with common difference between terms of 2. That is,

and we can solve for
in terms of
:



and so on down to

We solve for
in the same way.

Then



and so on down to

