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svet-max [94.6K]
2 years ago
10

A person is standing 50 yards from the base of a building. The angle of elevation from the person to the top of the building is

25-degrees. How tall is the building?

Mathematics
1 answer:
Whitepunk [10]2 years ago
6 0

Answer:

The height of the building is H = 11.65 yards

Step-by-step explanation:

Distance from the base of the building to the person = 50 yards

Angle of elevation = 25°

From Δ ABC

⇒ \tan 25 = \frac{H}{25}

⇒ H = 25 \tan 25

⇒ H = 11.65 yards

Therefore  the height of the building is H = 11.65 yards

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3 years ago
Find the missing lengths:<br> LO=5 and OK=4, find OH and KH.
hodyreva [135]

Answer:

The length of KH is 6 units and OH is 6.3 units.

Step-by-step explanation:

Given the figure with lengths LO=5 and OK=4. we have to find the length of  OH and KH.

In ΔLOH

By Pythagoras theorem

LH^2=LO^2+OH^2\\\\LH^2=5^2+OH^2 → (1)

In ΔKOH,

KH^2=OH^2+OK^2\\\\KH^2=OH^2+4^2  → (2)

In ΔKHL,

KL^2=LH^2+KH^2

Using eq (1) and (2), we get

KL^2=5^2+OH^2+OH^2+4^2

9^2=25+2OH^2+16

⇒ 2OH^2=81-25-16=40

⇒ OH=\sqrt{20}=6.324\sim6.3units.

Put the above value in eq 2, we get

KH^2=20+4^2=36

⇒ KH=6 units.

8 0
3 years ago
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