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mash [69]
3 years ago
11

A theater can seat 120 people. The number of rows is 7 less than the number of seats in each row. How many rows of seats are the

re?
Mathematics
1 answer:
jeka943 years ago
3 0

Let x be the number of rows.

If the number of rows is 7 less than the number of seats in each row, then the number of seats in a row is x+7. The total number of seats is

x·(x+7).

You know that a theater can seat 120 people, then

x·(x+7)=120.

Solve it:

x^2+7x-120=0,\\\\D=7^2-4\cdot (-120)=49+480=529,\ \sqrt{D}=23,\\\\x_1=\dfrac{-7+23}{2}=8, \ x_2=\dfrac{-7-23}{2}=-15.

The number of rows must be positive, then x=8.

Answer: there are 8 rows with 15 seats at each.

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AB=\sqrt{53},\ BC=\sqrt{40},\ CA=\sqrt{41}\\It\ is\ an\ acute\ triangle

Step-by-step explanation:

The distance between two points (x_1,y_1),\ (x_2,y_2) is given by \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

Here A(1,5),\ B(3,-2),\ C(-3,0) are the vertices of a triangle.

AB=\sqrt{(-2-5)^2+(3-1)^2}=\sqrt{(-7)^2+(2)^2}=\sqrt{49+4}=\sqrt{53}=7.28\ unit\\\\BC=\sqrt{(0+2)^2+(-3-3)^2}=\sqrt{(2)^2+(-6)^2}=\sqrt{4+36}=\sqrt{40}=6.32\ unit\\\\CA=\sqrt{(5-0)^2+(1+3)^2}=\sqrt{(5)^2+(4)^2}=\sqrt{25+16}=\sqrt{41}=6.40\ unit

Longest side=AB

AB^2=53\\BC^2+CA^2=40+41=81\\\Rightarrow AB^2

Hence this is an acute triangle.

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