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Ray Of Light [21]

3 years ago

6

What is the amplitude of a wave?

1 answer:

RideAnS [48]3 years ago

4 0

Its the distance from the center of the line of a wavelength

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• Give an example of a scientific theory that has changed. Did it become a scientific law, become obsolete, or become part of a

Agata [3.3K]

An example would be <span>Fleischmann-Pons's nuclear fusion theory, this theory tested the effects of what is known as "Cold Fusion", but when other scientists performed similar experiments they didn't achieve similar results, therefore making the theory obsolete.</span>

6 0

3 years ago

if you throw a rock straight up at a speed of 19m/s. How long goes it take the ball to reach its maximum height?

Scrat [10]

Answer:

It requires <u>1.9 seconds</u> to reach maximum height.

Explanation:

As per given question,

Initial velocity (U) =19 m/s

Final velocity (V) = 0 m/s

$\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}$

Maximum height = S

Time taken is "t"

<u>Calculating time taken to reach maximum height:</u>

We know that time taken to reach the maximum height is calculated by using the formula V = U + at

Substitute the given values in the above equation.

Final velocity is “0” as there is no velocity at the maximum height.

$0=19+10 \times t$

$-19=10 \times t$

$\frac{-19}{10}=t$

t = 1.9 seconds.

The time taken to reach maximum height is <u>1.9</u> seconds.

<u>Calculating maximum height</u>:

$\text { Consider the equation } V^{2}-U^{2}=2 a S$

Solving the equation we will get the value of S

$0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }$

-361 = -20S

Negative sign cancel both the sides.

$\mathrm{S}=\frac{361}{20}$

S = 18.05 m

Maximum height is 18.05 m .

3 0

3 years ago

If the ac peak voltage across a 100-ohm resistor is 120 V, then the average power dissipated by the resistor is ________

Kazeer [188]

Answer:

The average power dissipated is 72 W.

Explanation:

Given;

peak voltage of the AC circuit, V₀ = 120 V

resistance of the resistor, R = 100 -ohm

The average power dissipated by the resistor is given by;

$P_{avg} = \frac{1}{2} I_oV_o= I_{rms}V_{rms} = \frac{V_{rms}^2}{R}$

where;

$V_{rms}$ is the root-mean-square-voltage

$V_{rms} = \frac{V_o}{\sqrt{2}} \\\\V_{rms} = \frac{120}{\sqrt{2}}\\\\V_{rms} = 84.853 \ V$

The average power dissipated by the resistor is calculated as;

$P_{avg} = \frac{V_{rms}^2}{R}\\\\P_{avg} = \frac{84.853^2}{100}\\\\P_{avg} = 72 \ W$

Therefore, the average power dissipated is 72 W.

5 0

3 years ago

Students can take the aspire test in ninth and grade

Simora [160]

<em>The answer is </em>Ninth <em>and </em>Tenth <em>grade so the answer would be</em> B

<em>I hope this helps you </em>

3 0

3 years ago

Read 2 more answers

1 5kg cat is lifted 2 m into the air.how much gpe does it gain?

____ [38]

Answer:

<h3><em><u>Potential Energy= mgh = (5)(9.8)(2)= 98.</u></em></h3><h3 />

6 0

1 year ago