Question

A potential difference of 107 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative relative to the outer surface. How much work is required to eject a positive sodium ion (Na ) from the interior of the cell?

Answer 1

Answer:

The workdone is  $W = 1.712 *10^{-20 } \ J$  

Explanation:

From the question we are told that

    The potential difference is  $V = 107 mV = 107 *10^{-3} \ V$

Generally the charge on  $Na^{+}$ is  $Q_{Na^{+}} = 1.60 *10^{-19 } \ C$

 Generally the workdone is mathematically represented as

         $W = Q_{Na^{+}}V$

=>     $W = 1.60 *10^{-19 } * 107 *10^{-3}$    

=>     $W = 1.712 *10^{-20 } \ J$