Question

A wire is formed into a circle having a diameter of 11.1 cm and is placed in a uniform magnetic field of 2.79 mT. The wire carries a current of 5.00 A. Find the maximum torque on the wire.

Answer 1

Answer:

Maximum torque on the wire is $1.34\times 10^{-4}\ N-m$

Explanation:

It is given that,

Diameter of the wire, d = 11.1 cm = 0.111 m

Radius of wire, r = 0.0555 m

Magnetic field, $B=2.79\ mT=0.00279\ T$

Current, I = 5 A

We need to find the maximum torque on the wire. Torque is given by :

$\tau=IAB\ sin\theta$

Torque is maximum when, $\theta=90$

$\tau=IAB$

$\tau=5\times \pi \times (0.0555)^2\times 0.00279$

$\tau=0.000134\ N-m$

or

$\tau=1.34\times 10^{-4}\ N-m$

So, the maximum toque on the wire is $1.34\times 10^{-4}\ N-m$. Hence, this is the required solution.