Three consecutive odd integers have a sum of 27. Find the integers

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

4 0

You cant have consecutive odd integers it alternates beween odd and even? Ie. 1(odd), 2 (even), 3 (odd).

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solniwko [45]

Answer:

-3/5 or -0.6

Step-by-step explanation:

3 0

3 years ago

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Slav-nsk [51]

$\text{Consider the function}\\
\\
f(x)=6x^3-3\\
\\
\text{let }y=f(x), \text{ so we have}\\
\\
y=6x^3-3\\
\\
\text{now in order to find the inverse of the function, first we interchange x and y}\\
\text{so we get}\\
\\
x=6y^3-3$

$\text{now we will solve for y again and that will give the required inverse function.}\\
\text{so first we add 3 both sides to get}\\
\\
x+3=6y^3\\
\\
\text{now divide both sides by 6 to get}\\
\\
\frac{x+3}{6}=y^3\\
\\
\text{now take cube root both sides to get}\\
\\
\sqrt[3]{\frac{x+3}{6}}=\sqrt[3]{y^3}$

$\Rightarrow \sqrt[3]{\frac{x+3}{6}}=y\\
\\
\Rightarrow y=\sqrt[3]{\frac{x+3}{6}}\\
\\
\text{hence the inverse of the function is: }\\
\\
f^{-1}(x)=\sqrt[3]{\frac{x+3}{6}}$