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earnstyle [38]
3 years ago
10

A line segment can intersect a regular hexagon in ________?

Mathematics
2 answers:
Goryan [66]3 years ago
8 0
Six line segments! So number 3 would be correct.
sattari [20]3 years ago
7 0
The answer is 3. Six points

hope this helps
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Find the length of the missing side. Leave your answer in simplest radical form.
Hatshy [7]

Answer:

The SQ Root of 493

Step-by-step explanation:

Becaues this triangle is a right triangle, we can find the missing side usiing the pythagorean theorum.

The pythagorean theorun states A^2 + B^2 = C^2, so 18^2 + 13^2= 439

Then all you have to do is find the sq root of 439, but this question askes you not to.

Hope this helps :)

7 0
3 years ago
Give the appropriate theorem or postulate that can
vitfil [10]

Answer:

The right answer is A. AA Postulate

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2 years ago
Refer to the scenario below to answer the following question.
baherus [9]

Answer:

Tom's profit is 43,000.

Step-by-step explanation:

8 0
3 years ago
rotation of 90 degrees counterclockwise about the origin, point O, then a reflection across the x-axis reflection across the y-a
SpyIntel [72]

Answer:

The point O can be (x,y)  or (-x,y) or (-x,-y) or ( x,-y) reason being that you haven't given point O lies in which quadrant.

Rotation through 90° counter clockwise

(x,y) = (-y,x)

(-x,y)=(-y,-x)

(-x,-y)=(y,-x)

(x,-y) =(y,x)

Then Reflection across X axis has taken place.

(-y,x) = (-y,-x)

(-y,-x)=(-y,x)

(y,-x)=(y,x)

(y,x)=(y,-x)

Then a reflection across the y-axis has taken place.

(-y,-x)=(y,-x)

(-y,x) = (y,x)

(y,x) =(-y,x)

(y,-x)=(-y,-x)

Then a translation a units to the right and b units up has taken place.

(y,-x)=(y+a,-x+b)

(y,x) =(y+a, x+b)

(-y,x) =(-y+a,x+b)

(-y,-x)=(-y+a,-x+b)

Then a rotation of 180 degrees counterclockwise about the origin has taken place.

(y+a,-x+b)=[-(y+a),-(-x+b)]

(y+a, x+b)=[- (y+a), -(x+b)]

(-y+a,x+b)=[-(-y+a),-(x+b)]

(-y+a,-x+b) =[-(-y+a),-(-x+b)]

Now Again a reflection across the Y axis has taken place.

[-(y+a),-(-x+b)]=[(y+a),-(-x+b)]

[-(y+a),-(x+b)]=[(y+a),-(-x+b)]

[-(-y+a),-(x+b)]=[(-y+a),-(x+b)]

[-(-y+a),-(-x+b)]=[(-y+a),-(-x+b)]

Totally depends on value of a and b on which quadrant these point lies.



7 0
3 years ago
Can someone help me solve this
Scrat [10]

Answer:

your photo dose not work

Step-by-step explanation:

but you would half to email it to me then i can help you if you want to do that

8 0
3 years ago
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